【[LeetCode] 21. Merge Two Sorted Lists 混合插入有序链表】的更多相关文章

[LeetCode] 21. Merge Two Sorted Lists 混合插入有序链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相…

[LeetCode] Merge Two Sorted Lists 混合插入有序链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 这道混合插入有序链表和我之前那篇混合插入有序数组非常的相似Merge Sorted Array,仅仅是数据结构由数组换成了链表而已,代码写起来反而更简洁.具体思想就是新建一个链表,然后比较两个链表中的元素值,把较小的…

[LintCode] Merge Two Sorted Lists 混合插入有序链表

Merge two sorted (ascending) linked lists and return it as a new sorted list. The new sorted list should be made by splicing together the nodes of the two lists and sorted in ascending order. Have you met this question in a real interview? Yes Exampl…

[leetcode]21. Merge Two Sorted Lists合并两个链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题目 合并两个链表 思路 用dummy, 因为需要对头结…

21. Merge Two Sorted Lists (Java 合并有序链表 空间复杂度O(1))

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析:合并两个有序序列,这个归并排序中的一个关键步骤.这里是要合并两个有序的单链表.由于链表的特殊性,在合并时只需要常量的空间复杂度. 编码: public ListNode mergeTwoLists(Li…

[LeetCode] 21. Merge Two Sorted Lists 合并有序链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据…

[leetcode] 21. Merge Two Sorted Lists (Easy)

合并链表 Runtime: 4 ms, faster than 100.00% of C++ online submissions for Merge Two Sorted Lists. class Solution { public: ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) { //1 2 4 . 1 3 4 ListNode *res = ); ListNode *cur = res; while (l1 != NULL &&am…

LeetCode 21. Merge Two Sorted Lists （合并两个有序链表）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目标签:Linked List 题目给了我们两个lists,让我们有序的合并两个 lists. 这题利用递归可以从list 的最后开始向前链接nodes,代码很简洁,清楚. Java Solution: Runti…

LeetCode 21 -- Merge Two Sorted Lists

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. public ListNode mergeTwoLists(ListNode l1, ListNode l2) { ListNode p1 = l1; ListNode p2 = l2; ListNode fakeH…

Java [leetcode 21]Merge Two Sorted Lists

题目描述: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题思路: 题目的意思是将两个有序链表合成一个有序链表. 逐个比较加入到新的链表即可. 代码如下: public static ListNode mergeTwoLists(ListNode l1, Li…

[LeetCode] 21. Merge Two Sorted Lists 解题思路

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 问题:将两个已排序的列表,合并为一个有序列表. 令 head 为两个列表表头中较小的一个,令 p 为新的已排序的最后一个元素.令 l1, l2 分别为两个列表中未排序部分的首节点.依次将 l1, l2 中的较小值追加…

Leetcode 21. Merge Two Sorted Lists（easy）

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 递归实现: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(i…

(链表) leetcode 21. Merge Two Sorted Lists

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 中文:将两个有序链表合并为一个新的有序链表并返回.新链表…

# 蜗牛慢慢爬 LeetCode 21. Merge Two Sorted Lists [Difficulty: Easy]

题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 翻译 合并两个有序的链表 Hints Related Topics: LinkedList 参考 归并排序-维基百科,可以递归也可以迭代,基本的链表操作 代码 Java /** * Definition for…

[LeetCode] 21. Merge Two Sorted Lists ☆

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解法: 新建一个链表,依次比较两个链表的头元素,把较小的移到新链表中,直到有一个为空,再将另一个链表剩余元素移到新链表末尾. 采用循环的方式,代码如下: /** * Definition for singly-lin…

leetcode 21.Merge Two Sorted Lists ,java

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解决方案:276ms /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next…

[LeetCode]21. Merge Two Sorted Lists合并两个有序链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 list顺序合并就可以了 /** * Definitio…

LeetCode 21. Merge Two Sorted Lists合并两个有序链表 (C++)

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 分析: 将两个有序链表合并为一个新的有序链表并返…

LeetCode 21 Merge Two Sorted Lists （有序两个链表整合）

题目链接 https://leetcode.com/problems/merge-two-sorted-lists/?tab=Description   Problem: 已知两个有序链表(链表中的数值递增排列).将这两个链表进行合并操作,并且满足递增排列 即合并后仍为有序链表.     递归进行合并操作.mergeTwoList(ListNode list1, ListNode list2)      当list1==null时 return list2;      当list2==null时…

Leetcode 21 Merge Two Sorted Lists 链表

合并两个已排序的链表,考到烂得不能再烂的经典题,但是很多人写这段代码会有这样或那样的问题 这里我给出了我的C++算法实现 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(…

LeetCode 21. Merge Two Sorted Lists（c++)

要定义两个链表 判断时依次对应每一个链表的值进行判断即可. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { L…

leetcode 21 Merge Two Sorted Lists 合并两个有序链表

描述: 合并两个有序链表. 解决: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1) return l2; if (!l2) return l1; if (!l1 && !l2) return NULL; ListNode* ret = ); ListNode* now = ret; while (l1 || l2) { if (!l1) { now->next = l2; break; } else if…

LeetCode 21. Merge Two Sorted Lists（合并两个有序链表）

题意:合并两个有序链表 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if(l1 == NULL) retu…

[Leetcode][Python]21: Merge Two Sorted Lists

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 21: Merge Two Sorted Listshttps://oj.leetcode.com/problems/merge-two-sorted-lists/ Merge two sorted linked lists and return it as a new list.The new list should be made by splicing together…

leetCode练题——21. Merge Two Sorted Lists（照搬大神做法）

1.题目 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4-&g…

Java for LeetCode 023 Merge k Sorted Lists

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 解题思路一: 之前我们有mergeTwoLists(ListNode l1, ListNode l2)方法,直接调用的话,需要k-1次调用,每次调用都需要产生一个ListNode[],空间开销很大.如果采用分治的思想,对相邻的两个ListNode进行mergeTwoLists,每次将规模减少一半,直到…

21. Merge Two Sorted Lists(合并2个有序链表)

21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists 需要排序!!! [2,4][1] 输出1 2 4 而不是2 4 1  递归版!! class Solution { public ListNode mergeTwo…

21. Merge Two Sorted Lists【easy】

21. Merge Two Sorted Lists[easy] Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解法一: /** * Definition for singly-linked list. * struct ListNode { * int val…

21.Merge Two Sorted Lists 、23. Merge k Sorted Lists

21.Merge Two Sorted Lists 初始化一个指针作为开头,然后返回这个指针的next class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { ListNode* dummy = ); ListNode* p = dummy; while(l1 && l2){ if(l1->val <= l2->val){ p->next = l1; p = p-&…

刷题21. Merge Two Sorted Lists

一.题目说明 这个题目是21. Merge Two Sorted Lists,归并2个已排序的列表.难度是Easy! 二.我的解答 既然是简单的题目,应该一次搞定.确实1次就搞定了,但是性能太差: Runtime: 20 ms, faster than 8.74% of C++ online submissions for Merge Two Sorted Lists. Memory Usage: 9.4 MB, less than 5.74% of C++ online submissions…