题目描述: 自己的提交: class Solution: def twoSumBSTs(self, root1: TreeNode, root2: TreeNode, target: int) -> bool: if not root1 :return root_copy = root2 while root1 and root_copy: if root1.val + root_copy.val < target: root_copy = root_copy.right elif root1…

Given a binary search tree (BST) with duplicates, find all the mode(s) (the most frequently occurred element) in the given BST. Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than or equal to the nod…

Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Consider the following binary search tree: 5 / \ 2 6 / \ 1 3 Example 1: Input: [5,2…

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has…

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has…

Given a non-empty binary search tree and a target value, find k values in the BST that are closest to the target. Note: Given target value is a floating point. You may assume k is always valid, that is: k ≤ total nodes. You are guaranteed to have onl…

在以下讨论中,虽然任意复杂的关键字都是允许的,但为了简单起见,假设它们都是整数,并且所有的关键字是互异的. 总概   使二叉树成为二叉查找树的性质是,对于树中的每个节点X,它的左子树中所有关键字值小于X的关键字值,而它的右子树中所有的关键字值大于X的关键字值.注意,这意味着该树所有的元素可以用某种统一的方式排序. 操作 #ifndef __Tree_H struct TreeNode *Position; typedef struct TreeNode *SearchTree; SearchTr…

题目如下所示:返回的结果是一个Node的Vector: Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example,Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2…

构建二叉搜索树 /* 利用二叉搜索树的特点:根节点是中间的数 每次找到中间数,左右子树递归子数组 */ public TreeNode sortedArrayToBST(int[] nums) { return builder(nums,0,nums.length-1); } public TreeNode builder(int[] nums,int left,int right) { if (left>right) return null; int mid = (left+right)/2;…

给你 root1 和 root2 这两棵二叉搜索树. 请你返回一个列表,其中包含 两棵树 中的所有整数并按 升序 排序.. 示例 1: 输入:root1 = [2,1,4], root2 = [1,0,3] 输出:[0,1,1,2,3,4] 示例 2: 输入:root1 = [0,-10,10], root2 = [5,1,7,0,2] 输出:[-10,0,0,1,2,5,7,10] 示例 3: 输入:root1 = [], root2 = [5,1,7,0,2] 输出:[0,1,2,5,7]…