题意:有n个点,问其中某一对点的距离最小是多少 分析:分治法解决问题:先按照x坐标排序,求解(left, mid)和(mid+1, right)范围的最小值,然后类似区间合并,分离mid左右的点也求最小值 POJ 3714 #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> const int N = 1e5 + 5; const double INF = 1e…

Description After successive failures in the battles against the Union, the Empire retreated to its last stronghold. Depending on its powerful defense system, the Empire repelled the six waves of Union's attack. After several sleepless nights of thin…

平面最近点对 平面最近点对算是一个经典的问题了,虽然谈不上是什么专门的算法,但是拿出问题模型好好分析一个是有必要的. 给定\(n\)个二元组\((x,y)\),代表同一平面内的\(n\)个点的坐标,求\(\min\{dis_{(p,q)}\}\). 其中,定义\(dis_{(p,q)}\)代表两点的直线距离,即\(dis_{(p,q)}=\sqrt{(p_x-q_x)^2+(p_y-q_y)^2}\). \(Solution\ 1:\) 暴力求解,\(O(n^2)\)枚举两点,直接计算更新答案.…

Raid Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7473   Accepted: 2221 Description After successive failures in the battles against the Union, the Empire retreated to its last stronghold. Depending on its powerful defense system, the…

Description After successive failures in the battles against the Union, the Empire retreated to its last stronghold. Depending on its powerful defense system, the Empire repelled the six waves of Union's attack. After several sleepless nights of thin…

解题思路: 分治法求平面近期点对.点分成两部分,加个标记就好了. #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <cmath> #include <vector> #include <queue> #include <algorithm> #include <iomanip>…

题目:  http://poj.org/problem?id=3714 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=27048#problem/D Raid Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7355   Accepted: 2185 Description After successive failures in the battles aga…

题目链接:http://poj.org/problem?id=3714 分治算法修改该为两个点集的情况就可以了,加一个标记... //STATUS:C++_AC_2094MS_4880KB #include <functional> #include <algorithm> #include <iostream> //#include <ext/rope> #include <fstream> #include <sstream> #…

版权声明:本文作者靖心,靖空间地址:http://blog.csdn.net/kenden23/.未经本作者同意不得转载. https://blog.csdn.net/kenden23/article/details/36407517 本题是一般近期对点求解.略微添加点限定:有两个集合点,要求不同集合中的点的近期对. 那么就添加一个推断.假设是同一个集合中的点,那么就返回最大值.其它和一般的近期对点解法一样. 注意:本题数据有重合点.那么就要防止分类的时候溢出. Geeks上的近期对的程序是无法…

这个讲的好: https://phoenixzhao.github.io/%E6%B1%82%E6%9C%80%E8%BF%91%E5%AF%B9%E7%9A%84%E4%B8%89%E7%A7%8D%E6%96%B9%E6%B3%95/ 分治法 先空着 看一下这个第三个方法(随机增量哈希,O(n)) 1.千万不要用unordered_map/hash_map!T飞是肯定的:要手写哈希表,所以码量就很大:手写哈希表方法记一下 2.事实上以d为边长画格子,每次遍历相邻的9个格子,常数要比以d/2边…