Leetcode Integer Replacement】的更多相关文章

Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Input: 8 Outp…
Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Input: 8 Outp…
Question Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Inpu…
397. Integer Replacement QuestionEditorial Solution My Submissions   Total Accepted: 5878 Total Submissions: 21519 Difficulty: Easy Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can…
[LeetCode]397. Integer Replacement 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/integer-replacement/description/ 题目描述: Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you…
Week3 - 397. Integer Replacement 397.Integer Replacement - Medium Given a positive integer n and you can do operations as follow: 1.If n is even, replace n with n/2. 2.If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum num…
Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…
Convert a non-negative integer to its english words representation. Given input is guaranteed to be less than 231 - 1. For example, 123 -> "One Hundred Twenty Three" 12345 -> "Twelve Thousand Three Hundred Forty Five" 1234567 -&g…
Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 之前那篇文章写的是罗马数字转化成整数(http://www.cnblogs.com/grandyang/p/4120857.html), 这次变成了整数转化成罗马数字,基本算法还是一样.由于题目中限定了输入数字的范围(1 - 3999), 使得题目变得简单了不少. 基本字符 I V…
A typical CS style DP based solution: class Solution(object): def __init__(self): self.hm = {} def integerBreak(self, n): if n in self.hm: return self.hm[n] ret = 0 for i in range(1, n//2 + 1): v1 = self.integerBreak(i) v2 = self.integerBreak(n - i)…