Vases and Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 38    Accepted Submission(s): 10 Problem Description Alice is so popular that she can receive many flowers everyday. She has N v…

http://acm.hdu.edu.cn/showproblem.php?pid=4614 HDU 4614 Vases and Flowers (2013多校第二场线段树) // #pragma comment(linker, "/STACK:1024000000,1024000000") #include <iostream> #include <cstdio> #include <cstring> #include <sstream&g…

Vases and Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 347    Accepted Submission(s): 108 Problem Description Alice is so popular that she can receive many flowers everyday. She has…

Vases and Flowers Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 3220    Accepted Submission(s): 1273 Problem Description Alice is so popular that she can receive many flowers everyday. She ha…

Alice is so popular that she can receive many flowers everyday. She has N vases numbered from 0 to N-1. When she receive some flowers, she will try to put them in the vases, one flower in one vase. She randomly choose the vase A and try to put a flow…

描述Alice is so popular that she can receive many flowers everyday. She has N vases numbered from 0 to N-1. When she receive some flowers, she will try to put them in the vases, one flower in one vase. She randomly choose the vase A and try to put a fl…

Alice is so popular that she can receive many flowers everyday. She has N vases numbered from 0 to N-1. When she receive some flowers, she will try to put them in the vases, one flower in one vase. She randomly choose the vase A and try to put a flow…

http://acm.hdu.edu.cn/showproblem.php?pid=4614 Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others) Problem Description Alice is so popular that she can receive many flowers everyday. She has N vases numbered from 0 to…

题目0到n-1的花瓶,操作1在下标a开始插b朵花,输出始末下标.操作2清空[a,b]的花瓶,求清除的花的数量.线段树懒惰标记来更新区间.操作1,先查询0到a-1有num个空瓶子,然后用线段树的性质,或者二分找出第num+1个空瓶子的下标,和第num+b个空瓶子的下标.再区间更新为满.操作2,也相当于区间更新为空. #include<cstdio> #include<cstring> #include<algorithm> #define N 50001 using na…

题目链接 比赛的时候一直想用树状数组,但是树状数组区间更新之后,功能有局限性.线段树中的lz标记很强大,这个题的题意也挺纠结的. k = 1时,从a开始,插b个花,输出第一个插的位置,最后一个的位置,一个都没插,输出不能插. k = 2时,将[a,b]区间都清空,输出这个区间上本来有多少朵花. 主要是k = 1的时候,很难弄.给出区间[a,b]要找到第一个空花瓶,空花瓶的个数 = 总的-插花的个数 这肯定是一个单增的,所以利用二分求下界,这个位置,就是第一个空花瓶的位置,最后一个花瓶的位置需要特…