题目链接:https://vjudge.net/problem/HDU-3746 Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10985    Accepted Submission(s): 4692 Problem Description CC always becomes very depresse…

题目链接:https://cn.vjudge.net/problem/HDU-3746 题意 给一串珠子,我们可以在珠子的最右端或最左端加一些珠子 问做一条包含循环珠子的项链,最少还需要多少珠子 思路 KMP的另一个用法,求最小循环节minloop=len-fail[len] 用我的观点来看KMP的fail数组,就是值域和定义域都是串的长度,返回值是这个串能够匹配后缀的最大前缀串长度 但是纯循环节构成的串中,这个返回值不包括第一个循环节 比如aabaabaab fail[9]==6 fail[6…

题目链接:https://vjudge.net/problem/HDU-3746 知识点: KMP 解题思路: 论如何用 \(Next[]\) 数组求循环节. AC代码: #include <bits/stdc++.h> using namespace std; +; char inp[maxn]; int Next[maxn]; void init(int plen){ memset(Next,,sizeof(Next)); ,j=-; Next[]=-; while(i<plen){…

这题琢磨了挺长的时间.需要理解next[]表示了什么; next[i]代表了前缀和后缀的最大匹配的值,也就是个数. len-next[len]表示循环节的长度; 比如abcab   int fl=len-next[len]=3;循环节长度为3,即cab.然后int len=strlen(s)=5: 如果len%fl==0,那就count=len/fl,不然count=len/fl+1;count表示根据长度能够循环的次数.count*fl表示能够满足循环的时候的长度, count*fl-len就…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1946    Accepted Submission(s): 854 Problem Description CC always becomes very depressed at the end of this month, he has checked…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2716    Accepted Submission(s): 1244 Problem Description CC always becomes very depressed at the end of this month, he has checked…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6861    Accepted Submission(s): 2987 Problem Description CC always becomes very depressed at the end of this month, he has checked…

Cyclic Nacklace Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2538    Accepted Submission(s): 1154 Problem Description CC always becomes very depressed at the end of this month, he has checke…

题意 给你个字符串,问在字符串末尾还要添加几个字符,使得字符串循环2次以上. 解法 无论这个串是不是循环串 i-next[i] 都能求出它的最小循环节 代码: /* 思路:kmp+字符串的最小循环节问题 分析: 1 题目要求的是给定一个字符串,问我们还需要添加几个字符可以构成一个由n个循环节组成的字符串. 2 可知我们应该先求出字符串的最小循环节的长度:假设字符串的长度为len,那么最小的循环节就是cir = len-next[len] ; 如果有len%cir == 0,那么这个字符串就是已经…

CC always becomes very depressed at the end of this month, he has checked his credit card yesterday, without any surprise, there are only 99.9 yuan left. he is too distressed and thinking about how to tide over the last days. Being inspired by the en…