题目链接:http://poj.org/problem?id=3630 题意:给你多个字符串,如果其中任意两个字符串满足一个是另一个的前缀,那么输出NO,否则输出YES 思路:简单的trie树应用,插入的过程中维护到当前节点是不是字符串这个布尔量即可,同时判断是否存在上述情况. code: #include <iostream> #include <cstdio> #include <string> #include <cstring> using name…

POJ 3669 Meteor Shower(流星雨) Time Limit: 1000MS    Memory Limit: 65536K Description 题目描述 Bessie hears that an extraordinary meteor shower is coming; reports say that these meteors will crash into earth and destroy anything they hit. Anxious for her sa…

POJ 3253 Fence Repair (优先队列) Farmer John wants to repair a small length of the fence around the pasture. He measures the fence and finds that he needsN (1 ≤ N ≤ 20,000) planks of wood, each having some integer lengthLi (1 ≤ Li ≤ 50,000) units. He the…

[POJ 3071] Football(DP) Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4350   Accepted: 2222 Description Consider a single-elimination football tournament involving 2n teams, denoted 1, 2, -, 2n. In each round of the tournament, all tea…

Poj 3613 Cow Relays (图论) 题目大意 给出一个无向图,T条边,给出N,S,E,求S到E经过N条边的最短路径长度 理论上讲就是给了有n条边限制的最短路 solution 最一开始想到是的去直接统计最短路经过了多少条边,结果,,, 还是太年轻了... 不过,看数据范围只有1000,那么floyd是首选 回顾Floyd算法流程,其中的i到j松弛操作是通过k完成的 那么松弛一次就利用一个k点,我现在要经过n条边,那么松弛n次即可 详细说就是更新一次之后,把f[i][j]拷贝到原来的…

[python]Leetcode每日一题-前缀树(Trie) [题目描述] Trie(发音类似 "try")或者说 前缀树 是一种树形数据结构,用于高效地存储和检索字符串数据集中的键.这一数据结构有相当多的应用情景,例如自动补完和拼写检查. 请你实现 Trie 类: Trie() 初始化前缀树对象. void insert(String word) 向前缀树中插入字符串 word . boolean search(String word) 如果字符串 word 在前缀树中,返回 tru…

D - Jungle Roads Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1251 Description The Head Elder of the tropical island of Lagrishan has a problem. A burst of foreign aid money was spent on extr…

题意: 有s个不同的单词,给出一个长字符串把这个字符串分解成若干个单词的连接(可重复使用),有多少种分解方法 分析: dp[i]表示i开始的字符串能分解的方法数 dp[i]=sum(dp[i+len(x)]);单词x是i开始的字符串的前缀. #include <map> #include <set> #include <list> #include <cmath> #include <queue> #include <stack> #…

pid=1671">Phone List Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 12879    Accepted Submission(s): 4391 Problem Description Given a list of phone numbers, determine if it is consistent in…

Primitive Roots http://poj.org/problem?id=1284 Time Limit: 1000MS   Memory Limit: 10000K       Description We say that integer x, 0 < x < p, is a primitive root modulo odd prime p if and only if the set { (xi mod p) | 1 <= i <= p-1 } is equal…