Wormholes Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 36729   Accepted: 13444 Description While exploring his many farms, Farmer John has discovered a number of amazing wormholes. A wormhole is very peculiar because it is a one-way p…
Description While exploring his many farms, Farmer John has discovered a number of amazing wormholes. A wormhole is very peculiar because it is a one-way path that delivers you to its destination at a time that is BEFORE you entered the wormhole! Eac…
Wormholes Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 42366 Accepted: 15560 传送门 Description While exploring his many farms, Farmer John has discovered a number of amazing wormholes. A wormhole is very peculiar because it is a one-way p…
链接: http://poj.org/problem?id=3259 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22010#problem/B Wormholes Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25079   Accepted: 8946 Description While exploring his many farms, Farmer…
题目链接:http://poj.org/problem?id=3259 题目就是问你能否回到原点而且时间还倒回去了.题目中有些路中有单向的虫洞能让时间回到过去 所以只要将虫洞这条边的权值赋为负然后再判断有没有负环就行了. #include <iostream> #include <cstring> using namespace std; const int inf = 10001; int f , n , m , w ,dis[1001] , counts; struct TnT…
题意:给出n个点,m条正权的边,w条负权的边,问是否存在负环 因为Bellman_ford最多松弛n-1次, 因为从起点1终点n最多经过n-2个点,即最多松弛n-1次,如果第n次松弛还能成功的话,则说明存在有负环 #include<iostream> #include<cstdio> #include<cstring> #include <cmath> #include<stack> #include<vector> #include…
Description While exploring his many farms, Farmer John has discovered a number of amazing wormholes. A wormhole is very peculiar because it is a one-way path that delivers you to its destination at a time that is BEFORE you entered the wormhole! Eac…
1715: [Usaco2006 Dec]Wormholes 虫洞 Time Limit: 5 Sec  Memory Limit: 64 MB 注意第一次加边是双向边第二次是单向边,并且每次询问前数组要清空 Description John在他的农场中闲逛时发现了许多虫洞.虫洞可以看作一条十分奇特的有向边,并可以使你返回到过去的一个时刻(相对你进入虫洞之前).John的每个农场有M条小路(无向边)连接着N (从1..N标号)块地,并有W个虫洞.其中1<=N<=500,1<=M<=…
农夫约翰在探索他的许多农场,发现了一些惊人的虫洞.虫洞是很奇特的,因为它是一个单向通道,可让你进入虫洞的前达到目的地!他的N(1≤N≤500)个农场被编号为1..N,之间有M(1≤M≤2500)条路径,W(1≤W≤200)个虫洞.FJ作为一个狂热的时间旅行的爱好者,他要做到以下几点:开始在一个区域,通过一些路径和虫洞旅行,他要回到最开时出发的那个区域出发前的时间.也许他就能遇到自己了:).为了帮助FJ找出这是否是可以或不可以,他会为你提供F个农场的完整的映射到(1≤F≤5).所有的路径所花时间都…
poj 2049(二分+spfa判负环) 给你一堆字符串,若字符串x的后两个字符和y的前两个字符相连,那么x可向y连边.问字符串环的平均最小值是多少.1 ≤ n ≤ 100000,有多组数据. 首先根据套路,二分是显然的.然后跑一下spfa判断正环就行了. 然而我被no solution坑了十次提交.. #include <cctype> #include <cstdio> #include <cstring> using namespace std; const in…