HDOJ 5045 Contest】的更多相关文章

状压DP.. . . Contest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 666    Accepted Submission(s): 300 Problem Description In the ACM International Collegiate Programming Contest, each team cons…
Problem Description In the ACM International Collegiate Programming Contest, each team consist of three students. And the teams are given 5 hours to solve between 8 and 12 programming problems.  On Mars, there is programming contest, too. Each team c…
意甲冠军:N个人M通过主打歌有自己的期望,每个问题发送人玩.它不能超过随机播放的次数1,追求最大业绩预期 (1 ≤ N ≤ 10,1 ≤ M ≤ 1000). 主题链接:pid=5045" target="_blank">http://acm.hdu.edu.cn/showproblem.php?pid=5045 -->>设dp[i][j]表示已出战了前i - 1道题目,已出战的人的状态序列为j,如今要做第i道题目的最大期望.则最后要求的结果为max{dp[…
Contest Problem Description In the ACM International Collegiate Programming Contest, each team consist of three students. And the teams are given 5 hours to solve between 8 and 12 programming problems. On Mars, there is programming contest, too. Each…
pid=5045">主题链接~~> 做题感悟:比赛时这题后来才写的,有点小尴尬.两个人商议着写写了非常久才写出来,I want to Powerful ,I believe me . 解题思路: 遗憾 ! 感觉领悟能力太低 .由于随意时刻随意两个人做的题不超过 1 题 ,so~>  必须是一轮一轮的来(n 道题一轮),每一个人在一轮中仅仅能做一题.假设多做一题就,有可能某个人没选,某个人选择了两道,这样就不符合规定了 . 用 1  代表选择.0  代表没选择.进行某一行的时候就…
一道极其水的拓扑排序……但是我还是要把它发出来,原因很简单,连错12次…… 题意也很裸,前面的废话不用看,直接看输入 输入n, m表示从0到n-1共n个人,有m组关系 截下来m组,每组输入a, b表示a指向b,或者b指向a也行. 输入n == 0时结束 如果可以拓扑排序,输出"YES",否则输出"NO".每组输出占一行. 给两种代码吧,一种用邻接矩阵,另一种我也不知道叫什么好…… 邻接矩阵—— #include <cstdio> #include <…
题解:我们使用一个二位数组dp[i][j]记录进行到第i个任务时,人组合为j时的最大和(这里的j我们用二进制的每位相应一个人). 详细见代码: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> using namespace std; typedef long long ll; double s[11][1010]; double dp[1010][1050];…
题意: n和人做m道题, 每俩人做的题数不能相差一题以上.(也就是每n道题分别由n个人完成)   给n个人分别做m道题的概率, 求完成m题的最大期望 $1\le N \le 10$ 注意!!! fill dp 的地方!  [0, m]  所以要 m+1 !! #include <cstdio> #include <cstdlib> #include <cstring> #include <climits> #include <cctype> #i…
因为是circle sequence,可以在序列最后+序列前n项(或前k项);利用前缀和思想,预处理出前i个数的和为sum[i],则i~j的和就为sum[j]-sum[i-1],对于每个j,取最小的sum[i-1],这就转成一道单调队列了,维护k个数的最小值. ---------------------------------------------------------------------------------- #include<cstdio> #include<deque&…
LCIS Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5319    Accepted Submission(s): 2361 Problem Description Given n integers. You have two operations: U A B: replace the Ath number by B. (ind…