原题链接在这里:https://leetcode.com/problems/minimum-score-triangulation-of-polygon/ 题目: Given N, consider a convex N-sided polygon with vertices labelled A[0], A[i], ..., A[N-1] in clockwise order. Suppose you triangulate the polygon into N-2 triangles.  F…

Given N, consider a convex N-sided polygon with vertices labelled A[0], A[i], ..., A[N-1] in clockwise order. Suppose you triangulate the polygon into N-2 triangles.  For each triangle, the value of that triangle is the product of the labels of the v…

题目如下: Given N, consider a convex N-sided polygon with vertices labelled A[0], A[i], ..., A[N-1] in clockwise order. Suppose you triangulate the polygon into N-2 triangles.  For each triangle, the value of that triangle is the product of the labels of…

https://leetcode.com/problems/minimum-score-triangulation-of-polygon/ 题意:给定一个凸的N边形(N<=50),每个顶点有一个权值A[i],把它分为N-2个三角形,每个三角形的val等于三个顶点的权值的乘积,问划分之后图形的val总和最小为多少. 一开始想到了,问题可以转换为求解子问题,由于没有想到如何进行状态转换,并且感觉贪心可行, 如下图1,将当前图形可以构成的三角形找出(红线为底边),从中找到val最小的三角形如图2,然后…

这周比赛的题目很有特点.几道题都需要找到一定的技巧才能巧妙解决,和以往靠数据结构的题目不太一样. 就是如果懂原理,代码会很简单,如果暴力做,也能做出来,但是十分容易出错. 第四题还挺难想的,想了好久才想明白.这次先讲第四题,然后再讲其他的题目. 下面是详细的题解和思考. 比赛的地址 Weekly Contest 135 https://leetcode-cn.com/contest/weekly-contest-135 移动石子直到连续 II 题目:移动石子直到连续 II(Moving Ston…

Hello everyone, I am a Chinese noob programmer. I have practiced questions on leetcode.com for 2 years. During this time, I studied a lot from many Great Gods' articles. After worship, I always wanted to write an article as they did, and now I take t…

IMAQ Learn Pattern 2 VI 在匹配阶段创建您要搜索的图案匹配的模板图像的描述,此描述的数据被附加到输入模板图像中.在匹配阶段,从模板图像中提取模板描述符并且用于从检查图像中搜索模板. Image:是一个您要搜索模板图像的参考检查图像. Learn Pattern Setup Data(学习模式设置数据):是一个字符串,包含从本控件或从高级控件(IMAQ Advanced Setup Learn Pattern 2 VI)获得的信息.如果此引脚没有连接,在学习阶段VI使用默认参…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=648&page=show_problem&problem=5159 In normal football games, the winner team gets 3 points, loser team gets 0 point, and if there is a drawgame, bot…

C. Quiz time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Manao is taking part in a quiz. The quiz consists of n consecutive questions. A correct answer gives one point to the player. The gam…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Quiz Manao is taking part in a quiz. The quiz consists of n consecutive questions. A correct answer gives one point to the player. The game also has a counter of consecutive correct answers.…

这个课程的参考视频和图片来自youtube. 主要学到的知识点有: 1. Nested If-else statement (if-else ladder) /** * 90 and above ==> A * 80 up to 90 ==> B * 70 up to 80 ==> C * 60 up to 70 ==> D * below 60 ==> F */ if (grade >= 90) { gradeLetter = "A"; } els…

在playgroundm内键入以下代码,求一个成绩数组内最大分值和最小分值 func maxminScore(scores:Array<Int>) -> (maxScore:Int,minScore:Int)? { //一个可以空的Tuple if scores.isEmpty{ return nil  //判断是否有值,没值就返回一个空值 } var maxScore = scores[0], minScore = scores[0] for score in scores[1..&l…

In a world where ordinary people cannot reach, a boy named "Koutarou" and a girl named "Sena" are playing a video game. The game system of this video game is quite unique: in the process of playing this game, you need to constantly fac…

DreamGrid is playing the music game Live Love. He has just finished a song consisting of n notes and got a result sequence A​1​​,A​2​​,...,A​n​​ (A​i​​∈ {PERFECT, NON-PERFECT}). The score of the song is equal to the max-combo of the result sequence,…

传送门 题面: In a world where ordinary people cannot reach, a boy named "Koutarou" and a girl named "Sena" are playing a video game. The game system of this video game is quite unique: in the process of playing this game, you need to consta…

BE, GE or NE 23.58% 1000ms 262144K   In a world where ordinary people cannot reach, a boy named "Koutarou" and a girl named "Sena" are playing a video game. The game system of this video game is quite unique: in the process of playing…

In a world where ordinary people cannot reach, a boy named "Koutarou" and a girl named "Sena" are playing a video game. The game system of this video game is quite unique: in the process of playing this game, you need to constantly fac…

A Live Love DreamGrid is playing the music game Live Love. He has just finished a song consisting of n notes and got a result sequence A​1​​,A​2​​,...,A​n​​ (A​i​​∈ {PERFECT, NON-PERFECT}). The score of the song is equal to the max-combo of the resul…

2048这个游戏从刚出開始就风靡整个世界. 本技术博客的目的是想对2048涉及到相关的全部问题进行仔细的分析与讨论,得到一些大家能够接受而且理解的结果. 在这基础上,扩展2048的游戏性,使其变得更好玩.更有意思,更有耐玩性. 本技术博客涵盖了有关2048的策略.理论分析与讨论,代码简单剖析,以及代码扩展的思路.个人觉得应该是至今为止最全的2048游戏相关分析博客了.如有不论什么问题.有意思的讨论.以及想要交流的内容.欢迎大家留言~ 本篇为Part I,针对2048中各个问题进行分析与讨论. 题…

目录 A. Hard to prepare B.BE, GE or NE F.Features Track G.Trace H.Ryuji doesn't want to study I.Characters with Hash J. Maze Designer A. Hard to prepare After Incident, a feast is usually held in Hakurei Shrine. This time Reimu asked Kokoro to deliver…

Alice and Bob are going on a trip. Alice is a lazy girl who wants to minimize the total travelling distance, while Bob as an active boy wants to maximize it. At the same time, they cannot let the value to be less than a given integer L since that wil…

kube-scheduler源码分析(2)-核心处理逻辑分析 kube-scheduler简介 kube-scheduler组件是kubernetes中的核心组件之一,主要负责pod资源对象的调度工作,具体来说,kube-scheduler组件负责根据调度算法(包括预选算法和优选算法)将未调度的pod调度到合适的最优的node节点上. kube-scheduler架构图 kube-scheduler的大致组成和处理流程如下图,kube-scheduler对pod.node等对象进行了list/w…

D. Minimum Triangulation time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a regular polygon with nn vertices labeled from 11 to nn in counter-clockwise order. The triangulatio…

题意:求将一个n边形分解成(n-2)个三边形花费的最小精力,其中花费的精力是所有三角形的三顶点编号乘积的和(其中编号是按照顶点的顺时针顺序编写的) 考虑1,x,y连了一个三角形,x,y,z连了一个三角形.权值为xy+xyz. 换一种连接方法,1,x,z和1,y,z.权值为xz+yz 考虑x,y≥2时,x+y≤xy,所以后者剖分方法要优于前者剖分方法. 所以答案是(n³-n)÷3-2 AC代码: #include<bits/stdc++.h> using namespace std; int m…

题目链接 本题是区间dp里的三角剖分,板子题,dp[i][j]表示凸多边形i-j构成的最值,转移方程为dp[i][j] = min/max(dp[i][k]+dp[k][j]+w[i,j,k])(i<k<j),表示将凸多边形i-j以k为分界,分成i-k,k-j以及三角形i-j-k #include<bits/stdc++.h> using namespace std; #define lowbit(x) ((x)&(-x)) typedef long long LL; ty…

A General Polygon Clipping Library Version 2.32    http://www.cs.man.ac.uk/~toby/alan/software/gpc.html Alan Murta Advanced Interfaces Group Department of Computer Science University of Manchester Manchester M13 9PL, UK Abstract: This document descri…

http://poj.org/problem?id=1179 Polygon Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5078   Accepted: 2139 Description Polygon is a game for one player that starts on a polygon with N vertices, like the one in Figure 1, where N=4. Each…

Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5472   Accepted: 2334 Description Polygon is a game for one player that starts on a polygon with N vertices, like the one in Figure 1, where N=4. Each vertex is labelled with an integer and…

题目链接:http://poj.org/problem?id=1179 Time Limit: 1000MS Memory Limit: 10000K Description Polygon is a game for one player that starts on a polygon with N vertices, like the one in Figure 1, where N=4. Each vertex is labelled with an integer and each e…

B. Mister B and Angle in Polygon time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output On one quiet day all of sudden Mister B decided to draw angle a on his field. Aliens have already visited h…