Good Luck in CET-4 Everybody! Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8634    Accepted Submission(s): 5587 Problem Description 大 学英语四级考试就要来临了,你是不是在紧张的复习?也许紧张得连短学期的ACM都没工夫练习了,反正我知道的Kiki和C…

Stone Game, Why are you always there? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 393    Accepted Submission(s): 132 Problem Description “Alice and Bob are playing stone game...”“Err.... Fee…

kiki's game Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 40000/1000 K (Java/Others) Total Submission(s): 4972    Accepted Submission(s): 2908 Problem Description Recently kiki has nothing to do. While she is bored, an idea appears in his m…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4764 题意:Tang 和 Jiang 玩一个游戏,轮流写下一个数,Tang先手,第一次Tang只能写[1,k]之间的数,X表示上一个人写的数,Y表示下一个人写的数,每次必须满足 1<=Y-X<=k,直到有一个人写下的数不小于n,写下那个数的人失败,游戏结束,输出胜利的人. 分析:可以看做是取石子游戏,有一堆n-1个的石子,两个人轮流去石子,每次最多能去k个,如果没有石子可取则输,这就将问题转化为巴…

先在每堆中进行巴什博弈,然后尼姆 #include<stdio.h> int main() { int T; int i,n; int ans,m,l; scanf("%d",&T); while(T--) { scanf("%d",&n); ans=; ;i<=n;i++) { scanf("%d%d",&m,&l); ans=ans^(m%(l+)); } ) printf("Yes…

S-Nim Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7262    Accepted Submission(s): 3074 Problem Description Arthur and his sister Caroll have been playing a game called Nim for some time now.…

S-Nim Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3077    Accepted Submission(s): 1361 Problem Description Arthur and his sister Caroll have been playing a game called Nim for some time now…

Fibonacci again and again Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7663    Accepted Submission(s): 3205 Problem Description 任何一个大学生对菲波那契数列(Fibonacci numbers)应该都不会陌生,它是这样定义的:F(1)=1;F(2)=2;…

Brave Game Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 9475    Accepted Submission(s): 6308 Problem Description 十年前读大学的时候,中国每年都要从国外引进一些电影大片,其中有一部电影就叫<勇敢者的游戏>(英文名称:Zathura),一直到现在,我依然对于电影中的部…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4764 Problem Description Tang and Jiang are good friends. To decide whose treat it is for dinner, they are playing a game. Specifically, Tang and Jiang will alternatively write numbers (integers) on a wh…