Description Air Bovinia is planning to connect the N farms (1 <= N <= 200) that the cows live on. As with any airline, K of these farms (1 <= K <= 100, K <= N) have been selected as hubs. The farms are conveniently numbered 1..N, with farms…

4097: [Usaco2013 dec]Vacation Planning Description Air Bovinia is planning to connect the N farms (1 <= N <= 200) that the cows live on. As with any airline, K of these farms (1 <= K <= 100, K <= N) have been selected as hubs. The farms are…

[题目链接] https://www.lydsy.com/JudgeOnline/problem.php?id=4093 [算法] 对于k个枢纽 , 分别在正向图和反向图上跑dijkstra最短路 , 即可 时间复杂度 : O(K(N + M) log N) [代码] #include<bits/stdc++.h> using namespace std; #define MAXN 20010 #define MAXK 210 typedef long long LL; const LL in…

最近刷水太多标注一下防止它淹没在silver的水题中……我成为了本题,第一个T掉的人QAQ [题目大意] Bovinia设计了连接N (1 < = N < = 20,000)个农场的航班.对于任何航班,指定了其中的k个农场作为枢纽. (1 < = K <= 200 , K < = N). 目前,共有M种单向航班( 1 < = M < = 20,000 ),第i个航班从农场u_i至农场v_i花费d_i ( 1 < = d_i < =10,000 )美元.…

[BZOJ4094][Usaco2013 Dec]Optimal Milking Description Farmer John最近购买了N(1 <= N <= 40000)台挤奶机,编号为1 ... N,并排成一行.第i台挤奶机每天能够挤M(i )单位的牛奶 (1 < =M(i) <=100,000).由于机器间距离太近,使得两台相邻的机器不能在同一天使用.Farmer Jo hn可以自由选择不同的机器集合在不同的日子进行挤奶.在D(1 < = D < = 50,00…

4094: [Usaco2013 Dec]Optimal Milking Description Farmer John最近购买了N(1 <= N <= 40000)台挤奶机,编号为1 ... N,并排成一行.第i台挤奶机每天能够挤M(i)单位的牛奶 (1 < =M(i) <=100,000). 由于机器间距离太近,使得两台相邻的机器不能在同一天使用.Farmer John可以自由选择不同的机器集合在不同的日子进行挤奶. 在D(1 < = D < = 50,000)天中…

Description Farmer John has N cows that need to be milked (1 <= N <= 10,000), each of which takes only one unit of time to milk. Being impatient animals, some cows will refuse to be milked if Farmer John waits too long to milk them. More specificall…

Description Air Bovinia operates flights connecting the N farms that the cows live on (1 <= N <= 20,000). As with any airline, K of these farms have been designated as hubs (1 <= K <= 200, K <= N). Currently, Air Bovinia offers M one-way fl…

题目翻译不好,这里给出一份 题目背景 Awson是某国际学校信竞组的一只大佬.由于他太大佬了,于是干脆放弃了考前最后的集训,开车(他可是老司机)去度假.离开学校前,他打开地图,打算做些规划. 题目描述 他发现整个地图中有N(1<=N<=20000)个地点.对于所有的路线,指定了其中K(1<=K<=200,K<=N)个地点作为收费站.他设计了M(1<=M<=20000 )种单向的路线,第i条路线从地点Ui至Vi收费为Di(1<=Di<=10000).路线…

首先将排列和整个序列以及询问都反过来,问题变成给定一个位置$x$,问它经过若干轮置换后会到达哪个位置. 每次置换之后窗口都会往右滑动一个,因此其实真实置换是$p[i]-1$. 对于每个询问,求出轮数,倍增找到最终位置,注意当中途走到$0$时,说明离开了窗口,应及时终止. 时间复杂度$O((m+q)\log n)$. #include<cstdio> const int N=100010,M=30; int n,m,q,i,j,x,r,k,a[M][N]; inline void read(in…