Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

原题链接在这里:https://leetcode.com/problems/minimum-index-sum-of-two-lists/description/ 题目: Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find…

［抄题］: Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice ti…

problem 599. Minimum Index Sum of Two Lists 题意:给出两个字符串数组,找到坐标位置之和最小的相同的字符串. 计算两个的坐标之和,如果与最小坐标和sum相同,那么将这个字符串加入结果res中,如果比sum小,那么sum更新为这个较小值,然后将结果res清空并加入这个字符串. solution: class Solution { public: vector<string> findRestaurant(vector<string>&…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

题目: 假设 Andy 和 Doris 想在晚餐时选择一家餐厅,并且他们都有一个表示最喜爱餐厅的列表,每个餐厅的名字用字符串表示. Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. 你需要帮助他们用最少的索引和找出他们共同喜爱的餐厅.如果答案不止一个,则输出所有答案并且不考虑…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:找到公共元素再求索引和 方法二:索引求和,使用堆弹出最小元素 日期 题目地址:https://leetcode.com/problems/minimum-index-sum-of-two-lists/description/ 题目描述 Suppose Andy and Doris want to choose a restaurant for…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3802 访问. 假设Andy和Doris想在晚餐时选择一家餐厅,并且他们都有一个表示最喜爱餐厅的列表,每个餐厅的名字用字符串表示. 你需要帮助他们用最少的索引和找出他们共同喜爱的餐厅. 如果答案不止一个,则输出所有答案并且不考虑顺序. 你可以假设总是存在一个答案. 输入: ["Shogun", "Tapioca Express", &…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

题目描述 Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie…

这是悦乐书的第272次更新,第286篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第139题(顺位题号是599).假设Andy和Doris想要选择一家餐馆吃晚餐,他们都有一个最受欢迎的餐馆列表.你需要用最少的列表索引总和帮助他们找出他们的共同兴趣.如果答案之间存在选择关系,则输出所有答案并且没有顺序要求.你可以假设总有一个答案.例如: 输入: ["Shogun", "Tapioca Express", "Burger King…

1.题目描述 2.问题分析 直接是用hash table 解决问题 3.代码 vector<string> findRestaurant(vector<string>& list1, vector<string>& list2) { vector<string> result; map<string,int>m; ; i < list1.size() ; i++ ) { m.insert( std::pair<stri…

假设Andy和Doris想在晚餐时选择一家餐厅,并且他们都有一个表示最喜爱餐厅的列表,每个餐厅的名字用字符串表示. 你需要帮助他们用最少的索引和找出他们共同喜爱的餐厅. 如果答案不止一个,则输出所有答案并且不考虑顺序. 你可以假设总是存在一个答案. 示例 1: 输入: ["Shogun", "Tapioca Express", "Burger King", "KFC"] ["Piatti", "T…

一个按钮提交两个表单,有时候会用到,一般会很容易想到使用 onclick="document.form1.submit();document.form2.submit();" 的方法往往只会提交最后一个表单,前面一个会莫名其妙的忽略不计,有人提议使用下面的方法: 1)<script language="vbscript"> sub form1_onsubmit() form2.submit end sub</script>//1的方法不能用在…

问题:如果vue的同一个页面拥有两个表单.验证第一个表单时没有通过就切换到第二个,那么第二个表单会出现验证错误的信息 我们可以通过为两个表单添加ref属性 之后在通过调用resetFields()方法来解决问题 代码如下 <el-form :model="form" :rules="rules" ref="form" label-width="100px"> this.$refs["form"]…

引言 二维动态规划中最常见的是棋盘型二维动态规划. 即 func(i, j) 往往只和 func(i-1, j-1), func(i-1, j) 以及 func(i, j-1) 有关 这种情况下,时间复杂度 O(n*n),空间复杂度往往可以优化为O(n) 例题  1 Minimum Path Sum  Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right whi…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.You need to help them find out their common interest with the least list index sum. If there is a choice tie betwe…

Minimum Path Sum Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. SOLUTION 1: 相当基础…

在VB.NET程序开发过程中遇到一个问题 提交一个表单时,button的html代码如下 <asp:Button ID="btnSubmit" OnClick="cmdSubmit" runat="server" CssClass="btn btn-default" Text="Send" CausesValidation="true" /> 后台代码如下: Sub cmdS…

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 这道题跟之前那道Dungeon Game 地牢游戏 没有什么太大的…

原题地址:https://oj.leetcode.com/problems/minimum-path-sum/ 题意: Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or r…

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 做这题之前,建议先看一下Leetcode Triangle 这题看…

题目链接 Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 典型的动态规划问题. 设dp[i][j]表示从左上角到g…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists have…

题意: 给一个n*m的矩阵,每次可以往下或右走,经过的格子中的数字之和就是答案了,答案最小为多少? 思路: 比较水,只是各种空间利用率而已. 如果可以在原空间上作修改. class Solution { public: int minPathSum(vector<vector<int>>& grid) { ; ; ; j<=m; j++) grid[][j]+=grid[][j-]; ; i<=n; i++) { grid[i][]+=grid[i-][]; ;…

今天看到一篇博客谈论get和post区别,简单总结一下https://www.cnblogs.com/logsharing/p/8448446.html 要说两者的区别,接触过web开发的人基本上都能说出一二,最直观的区别是get把参数包含在url中,post通过request body传递参数. 然后你轻轻松松给出了一个标准答案: 1.GET在浏览器回退时是无害的,而post会再次提交请求. 2.GET产生的url地址可以被Bookmark而post不可以 3.GET请求会被浏览器主动cach…

原始form表单值获取方式(手动): $.ajax({ type: "POST", url: "ajax.php", data: "Name=摘取天上星&position=IT技术", success: function(msg){alert(msg);}, error: function(error){alert(error);} }); JQ serialize()方法取值: $.ajax({ type: "POST&quo…