The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number theoreticians for thousands of years is the question of primality. A prime number is a number that is has no prop…
一个数 $n$ 必有一个不超过 $\sqrt n$ 的质因子. 打表处理出 $1$ 到 $\sqrt n$ 的质因子后去筛掉属于 $L$ 到 $R$ 区间的素数即可. Code: #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> using namespace std; const int Range=50000; const int N=1000000+233…
Prime Distance Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12811   Accepted: 3420 Description The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number th…
题目链接:传送门 题目: Prime Distance Time Limit: 1000MS Memory Limit: 65536K Total Submissions: Accepted: Description The branch of mathematics called number theory and itself). The first prime numbers are ,,, but they quickly become less frequent. One of the…
http://poj.org/problem?id=2689 题意:给出一个大区间[L,U],分别求出该区间内连续的相差最小和相差最大的素数对. 由于L<U<=2147483647,直接筛素数是不行的,数组就开不了.可是能够依据素数筛的原理.我们先筛出sqrt(2147483647)以内的素数,然后拿这些素数去筛[L,U]之间的素数,即两次素数筛.可是L,U还是非常大,但U-L<=1000000,所以进行区间平移,将[L,U]平移为[0,U-L],就能用数组放得下. #include &…
The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number theoreticians for thousands of years is the question of primality. A prime number is a number that is has no prop…
The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number theoreticians for thousands of years is the question of primality. A prime number is a number that is has no prop…
称号: 给出一个区间[L,R]求在该区间内的素数最短,最长距离. (R < 2 * 10^9 , R - L <= 10 ^ 6) 由数论知识可得一个数的因子可在开根号内得到. 所以,我们能够打出5*10^4内得素数.然后,在用一次筛法把在[L.R]内得合数找到,则剩下的就是素数了.这里要用到离散化.把一个数 x - L 保存在数组里.由于,直接保存肯定不行.可是我们发现区间特点较小.所以.能够想到离散化. #include <iostream> #include <algo…
Sample Input 2 17 14 17 Sample Output 2,3 are closest, 7,11 are most distant. There are no adjacent primes. 找出给定范围内,距离最远和最近的素数.(不停超时 - -) 给的上界很大,所以全处理肯定不行. 先处理sqrt(2147483647). 然后再在l 与 r之间筛选素数. #include <cstdio> #include <cstring> #include <…
/* * 二次筛素数 * POJ268----Prime Distance(数论,素数筛) */ #include<cstdio> #include<vector> using namespace std; const int maxn = 1000005; typedef long long LL; bool is_prime_small[maxn]; bool is_prime[maxn]; vector <int> res; int main() { LL l,u…