Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

题意: 判断两个字符串是否互为Scramble字符串,而互为Scramble字符串的定义: 字符串看作是父节点,从字符串某一处切开,生成的两个子串分别是父串的左右子树,再对切开生成的两个子串继续切开,直到无法再切,此时生成为一棵二叉树.对二叉树的任一子树可任意交换其左右分支,如果S1可以通过交换变成S2,则S1,S2互为Scramble字符串. 思路: 对于分割后的子串,应有IsScramble(s1[0,i] , s2[0,i]) && IsSCramble(s1[i,length] ,…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

原题地址 两个字符串满足什么条件才称得上是scramble的呢? 如果s1和s2的长度等于1,显然只有s1=s2时才是scramble关系. 如果s1和s2的长度大于1,那么就对s1和s2进行分割,划分成两个子问题分别处理. 如何分割呢?当然不能任意分割.假设分割后s1变成了s11和s12,s2变成了s21和s22,那么只有2种分割方式: 1. s11.length = s21.length & s12.length = s22.length,如下图所示: s1: ? ? ? ? ? -----…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s…

Scramble String Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the s…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 动态规划 日期 题目地址:https://leetcode.com/problems/scramble-string/description/ 题目描述 Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty subs…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

将一个单词按照这种方式分: Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may choose any non-leaf node and swap its two children. For example, if we choose the node "gr" an…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

题目描述 LeetCode 344. 反转字符串 请编写一个函数,其功能是将输入的字符串反转过来. 示例 输入: s = "hello" 返回: "olleh" Java 解答 class Solution { public String reverseString(String s) { if (s == null || s.length() <= 1) { return s; } char[] arr = s.toCharArray(); int leng…

给定一个字符串 s1,我们可以把它递归地分割成两个非空子字符串,从而将其表示为二叉树.下图是字符串s1 = "great"的一种可能的表示形式.    great   /    \  gr    eat / \    /  \g   r  e   at           / \          a   t在扰乱这个字符串的过程中,我们可以挑选任何一个非叶节点,然后交换它的两个子节点.例如:如果我们挑选非叶节点 "gr",交换它的两个子节点,将会产生扰乱字符串&q…

Given a string S, check if the letters can be rearranged so that two characters that are adjacent to each other are not the same. If possible, output any possible result.  If not possible, return the empty string. Example 1: Input: S = "aab" Out…

Given an encoded string, return it's decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer. You may assume th…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may ch…

转:http://www.cnblogs.com/easonliu/p/3696135.html 分析:这个问题是google的面试题.由于一个字符串有很多种二叉表示法,貌似很难判断两个字符串是否可以做这样的变换.对付复杂问题的方法是从简单的特例来思考,从而找出规律.先考察简单情况:字符串长度为1:很明显,两个字符串必须完全相同才可以.字符串长度为2:当s1="ab", s2只有"ab"或者"ba"才可以.对于任意长度的字符串,我们可以把字符串s…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": To scramble the string, we may choose any non-leaf node and swap its two ch…

Write a function that reverses a string. The input string is given as an array of characters char[]. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. You may assume all the…

本文始发于个人公众号:TechFlow,原创不易,求个关注 今天是LeetCode专题第54篇文章,我们一起来看LeetCode 87题,Scramble String(爬行字符串). 这题的官方难度是Hard,通过率33%,点赞506,反对702.看起来这题难度还可以,但是反对比点赞多,其实这题质量还不错,反对比较多我猜可能是因为题意稍稍有些复杂,理解起来不太容易,编码也偏难.但是这题如果是放在正式比赛中出现的话,都不叫事. 下面我们来看下题意. 题意 这题的题目叫做爬取字符串,看起来有些费解…

Hard! 题目描述: 给定一个字符串 s1,我们可以把它递归地分割成两个非空子字符串,从而将其表示为二叉树. 下图是字符串 s1 = "great" 的一种可能的表示形式. great / \ gr eat / \ / \ g r e at / \ a t 在扰乱这个字符串的过程中,我们可以挑选任何一个非叶节点,然后交换它的两个子节点. 例如,如果我们挑选非叶节点 "gr" ,交换它的两个子节点,将会产生扰乱字符串 "rgeat" . rgea…

Scramble String Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the s…

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 ="great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we may cho…