leetcode 20 括号匹配

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leetcode 20 括号匹配

class Solution { public: bool isValid(string s) { stack<char> result; for(char c:s){ if(c == '(' || c == '[' || c == '{') result.push(c); else{ if(result.empty()) return false; if(c == ')' && result.top() != '(') return false; if(c == ']' &a…

leetcode 栈括号匹配

https://oj.leetcode.com/problems/valid-parentheses/ 遇到左括号入栈,遇到右括号出栈找匹配,为空或不匹配为空, public class Solution { public boolean isValid(String s) { char c[]=s.toCharArray(); Stack<Character> stack=new Stack<Character>(); for(int i=0;i<s.length();i+…

LeetCode 20 Valid Parentheses （括号匹配问题）

题目链接 https://leetcode.com/problems/valid-parentheses/?tab=Description Problem: 括号匹配问题. 使用栈,先进后出! 参考代码1: package leetcode_50; import java.util.Stack; /*** * * @author pengfei_zheng * 括号匹配问题 */ public class Solution20 { public static boolean isVali…

《LeetBook》leetcode题解(20):Valid Parentheses[E]——栈解决括号匹配问题

我现在在做一个叫<leetbook>的免费开源书项目,力求提供最易懂的中文思路,目前把解题思路都同步更新到gitbook上了,需要的同学可以去看看书的地址:https://hk029.gitbooks.io/leetbook/ 20. Valid Parentheses 问题 Given a string containing just the characters ‘(‘, ‘)’, ‘{‘, ‘}’, ‘[’ and ‘]’, determine if the input string…

LeetCode 第20题--括号匹配

1. 题目 2.题目分析与思路 3.代码 1. 题目给定一个只包括 '(',')','{','}','[',']' 的字符串,判断字符串是否有效. 有效字符串需满足: 左括号必须用相同类型的右括号闭合.左括号必须以正确的顺序闭合.注意空字符串可被认为是有效字符串. 2. 思路这道题是简单题,所以使用栈的思想进行括号匹配就可以,要让代码变得简单,可以使用字典,使得条件判断变得简洁. 3. 代码 class Solution: def isValid(self, s: str) -> bool:…

[leetcode]20. Valid Parentheses有效括号序列

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct…

[LeetCode]20. Valid Parentheses有效的括号

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct…