Day4 - I - Trucking HDU - 2962】的更多相关文章

A certain local trucking company would like to transport some goods on a cargo truck from one place to another. It is desirable to transport as much goods as possible each trip. Unfortunately, one cannot always use the roads in the shortest route: so…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2962 Trucking Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1763    Accepted Submission(s): 618 Problem Description A certain local trucking co…
Trucking Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2216    Accepted Submission(s): 757 Problem Description A certain local trucking company would like to transport some goods on a cargo…
Trucking Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1692    Accepted Submission(s): 587 Problem Description A certain local trucking company would like to transport some goods on a cargo…
Trucking A certain local trucking company would like to transport some goods on a cargo truck from one place to another. It is desirable to transport as much goods as possible each trip. Unfortunately, one cannot always use the roads in the shortest…
题目大意:给定无向图,每一条路上都有限重,求能到达目的地的最大限重,同时算出其最短路. 题解:由于有限重,所以二分检索,将二分的值代入最短路中,不断保存和更新即可. #include <cstdio> #include <cstring> #include <utility> #include <queue> using namespace std; const int N=20005; const int INF=9999999; typedef pair…
Trucking Problem Description A certain local trucking company would like to transport some goods on a cargo truck from one place to another. It is desirable to transport as much goods as possible each trip. Unfortunately, one cannot always use the ro…
1967年,美国著名的社会学家斯坦利·米尔格兰姆提出了一个名为“小世界现象(small world phenomenon)”的著名假说,大意是说,任何2个素不相识的人中间最多只隔着6个人,即只用6个人就可以将他们联系在一起,因此他的理论也被称为“六度分离”理论(six degrees of separation).虽然米尔格兰姆的理论屡屡应验,一直也有很多社会学家对其兴趣浓厚,但是在30多年的时间里,它从来就没有得到过严谨的证明,只是一种带有传奇色彩的假说而已. Lele对这个理论相当有兴趣,于…
题意:最短路上有一条高度限制,给起点和最大高度,求满足高度最大情况下,最短路的距离 不明白为什么枚举所有高度就不对 #include<cstdio> #include<cstring> #include<algorithm> ; ][][],dist[],H[]; using namespace std; int n,line; int i,j,k; int st,ed,mid; ; ]; ]; bool dijkstra() { ]; ;i<=n;i++) {…
题目 题意 给出一张图,每条道路有限高,给出车子的起点,终点,最高高度,问在保证高度尽可能高的情况下的最短路,如果不存在输出 $ cannot  reach  destination $ 跟前面 $ hdu5418 $ 一样的,题目挺基础的,但是在细节方面比较抠.要是最高度尽可能高,我们就可以想去枚举可能的高度去跑 $ spfa $ ,但我们可以发现这样效率太低了,那么我们为什么不二分答案呢?给出最高高度了,最低不就是 $ 0 $ 吗?二分答案再去跑 $ spfa $ 加上限制条件. 这题时限…