感觉题意不太好懂 = =# 给两个字符串 问是否等价等价的定义(满足其中一个条件):1.两个字符串相等 2.字符串均分成两个子串,子串分别等价 因为超时加了ok函数剪枝,93ms过的. #include <iostream> #include <cstring> #define clr(x,c) memset(x,c,sizeof(x)) using namespace std; const int N = 200005; char s[N], t[N]; int sc[30],…

Equivalent Strings   E - 暴力求解.DFS Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Description Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length ar…

Equivalent Strings 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=84562#problem/E 题意: 给出两个字符串,确定是否相等.一个字符串分割成相同大小的两半a1和a2,另一个字符串分割成相同大小的成两半b1和b2. 以下是正确的:a1相当于b1 ,a2相当于b2a1相当于b2 ,a2相当于b1 Sample Input Input aabaabaa Output YES Input aabbaba…

D. Equivalent Strings Time Limit: 2 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/559/problem/B Description Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are…

B. Equivalent Strings Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/559/problem/B Description Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are…

559B - Equivalent Strings 思路:字符串处理,分治 不要用substr(),会超时 AC代码: #include<bits/stdc++.h> #include<cstring> using namespace std; #define ll long long ; bool cmp(char a[],char b[],int l) { bool ans=true; ;i<l;i++)if(a[i]!=b[i])ans=false; return an…

D. Equivalent Strings time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal l…

Equivalent Strings Problem's Link: http://codeforces.com/contest/559/problem/B Mean: 给定两个等长串s1,s2,判断是否等价. 等价的含义为: 若长度为奇数,则必须是相同串. 若长度是偶数,则将两串都均分成长度为原串一半的两个子串l1,r1和l2,r2,其中l1和l2等价且r1和r2等价,或者l1和r2等价且l2和r1等价. analyse: 直接按照题意模拟写个递归分治就行.比赛的时候总觉得这样暴力写会TLE,…

D. Equivalent Strings time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal l…

Submit Status Description Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalent in one of the two cases: They are equal. If we split string a into two halves…

time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalen…

Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalent in one of the two cases: They are equal. If we split string a into two halves of the same size a1 and a2…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…

题目链接: 题目 D. Alyona and Strings time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output 问题描述 After returned from forest, Alyona started reading a book. She noticed strings s and t, lengths of which are…

Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&…

转载:43. Multiply Strings 题目描述 就是两个数相乘,输出结果,只不过数字很大很大,都是用 String 存储的.也就是传说中的大数相乘. 解法一 我们就模仿我们在纸上做乘法的过程写出一个算法. 个位乘个位,得出一个数,然后个位乘十位,全部乘完以后,就再用十位乘以各个位.然后百位乘以各个位,最后将每次得出的数相加.十位的结果要补 1 个 0 ,百位的结果要补两个 0 .相加的话我们可以直接用之前的大数相加.直接看代码吧. public String multiply(Stri…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 给出两个字符串,返回对应数字想乘后的字符串,由于这个字符串可能很大,所以不能采用一般的乘法,这里用的方法是模拟手工的乘法运算,算法 本身很简单,就是当时写的时候有些很小的细节搞错了,找了…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意:计算字符串对应数字的乘积.参考JustDoIT的博客. 思路:先用一维向量存放计算的中间值,中间值存放对应位置乘积的和(暂不考虑进位的情况):然后针对进位的情况,进行计算:注意要跳…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 要求:字符串表示的数字可能无穷大,并且非负. class Solution { private: vector<string> tempStrs; public: string add…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…

判断两个字符串是否同构 hs,ht就是每个字符出现的顺序 "egg" 与"add"的数字都是122 "foo"是122, 而"bar"是123 class Solution { public: bool isIsomorphic(string s, string t) { ] = {}; ] = {}; if (s.size() != t.size()) return false; ; ;i<s.size(); ++i)…

Constructors 构造函数,用于字符串初始化 Operators 操作符,用于字符串比较和赋值 append() 在字符串的末尾添加文本 assign() 为字符串赋新值 at() 按给定索引值返回字符 begin() 返回一个迭代器,指向第一个字符 c_str() 将字符串以C字符数组的形式返回 capacity() 返回重新分配空间前的字符容量 compare() 比较两个字符串 copy() 将内容复制为一个字符数组 data() 返回内容的字符数组形式 empty() 如果字符串…

题意: 定义a为一个字符串,a*a表示两个字符相连,即 an+1=a*an ,也就是出现循环了.给定一个字符串,若将其表示成an,问n最大为多少? 思路: 如果完全不循环,顶多就是类似于abc1这样,即n=1.但是如果循环出现了,比如abab,那就可以表示成(ab)2.还有一点,就是要使得n尽量大,那么当出现abababab时,应该要这么表示(ab)4,而不是(abab)2. 此题用神奇的KMP解决,也就是主要利用next数组.举例说明. 一般出现循环的都会大概是这样的:abcabcabc.而这…

http://www.bnuoj.com/bnuoj/problem_show.php?pid=29375 [题意]:可以对两字符串进行如下操作: 1.可以无损耗交换相邻两个字符(可以理解成交换任意字符) 2.可以改变一个字符 x->y ,花费为 x-y 的绝对值 求花费最少,将两字符串变成一样 [题解]: 排序字符串,然后对应相减 [code]: #include <iostream> #include <stdio.h> #include <math.h> #…

原文链接https://www.cnblogs.com/zhouzhendong/p/CF542E.html 题目传送门 - CF452E 题意 给定三个字符串 $s1,s2,s3$ ,对于所有 $L\in{1,2,\cdots,min(|s1|,|s2|,|s3|)}$ ,输出 $f(L)$ . 其中 $f(L)$ 表示满足 $s_k[i_k,\cdots,i_k+L-1]$ 全部相同的 $i_1,i_2,i_3$ 的个数. 答案对 $10^9+7$ 取模. $|s1|+|s2|+|s3|\l…

题意:定义了字符串的相等,问两串是否相等. 卡了时间,空间,不能新建字符串,否则会卡. #pragma comment(linker,"/STACK:1024000000,1024000000") #include<iostream> #include<cstdio> #include<string> #include<cstring> #include<vector> #include<cmath> #inclu…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. string multiply(string& num, char ch){ '; string s; ; int x; ; i>=; i--){ x = (num[i]-') *…

之所以抛弃char*的字符串而选用C++标准程序库中的string类,是因为他和前者比较起来,不必担心内存是否足够.字符串长度等等,而且作为一个类出现,他集成的操作函数足以完成我们大多数情况下(甚至是100%)的需要.我们可以用 = 进行赋值操作,== 进行比较,+ 做串联(是不是很简单?).我们尽可以把它看成是C++的基本数据类型.    好了,进入正题………首先,为了在我们的程序中使用string类型,我们必须包含头文件 <string>.如下:    #include <strin…