HDU 5249 离线树状数组求第k大+离散化

【HDU 5249 离线树状数组求第k大+离散化】的更多相关文章

HDU 5249 离线树状数组求第k大+离散化

KPI Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1160 Accepted Submission(s): 488 Problem Description 你工作以后, KPI 就是你的全部了. 我开发了一个服务,取得了很大的知名度.数十亿的请求被推到一个大管道后同时服务从管头拉取请求.让我们来定义每个请求都有一个重要值.我的…

poj 2985 The k-th Largest Group 树状数组求第K大

The k-th Largest Group Time Limit: 2000MS Memory Limit: 131072K Total Submissions: 8353 Accepted: 2712 Description Newman likes playing with cats. He possesses lots of cats in his home. Because the number of cats is really huge, Newman wants to g…

POJ2985 The k-th Largest Group[树状数组求第k大值+并查集||treap+并查集]

The k-th Largest Group Time Limit: 2000MS Memory Limit: 131072K Total Submissions: 8807 Accepted: 2875 Description Newman likes playing with cats. He possesses lots of cats in his home. Because the number of cats is really huge, Newman wants to g…

树状数组求第K大（From CLJ）

; <<log2[n];p;p>>=) if(a[ret+p]<=kth) kth-=a[ret+=p]; return ret;…

hdu 4217 Data Structure? 树状数组求第K小

Data Structure? Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Problem Description Data structure is one of the basic skills for Computer Science students, which is a particular way of storing and organizing data…

树状数组求第k小的元素

int find_kth(int k) { int ans = 0,cnt = 0; for (int i = 20;i >= 0;i--) //这里的20适当的取值,与MAX_VAL有关,一般取lg(MAX_VAL) { ans += (1 << i); if (ans >= maxn || cnt + c[ans] >= k) ans -= (1 << i); else cnt += c[ans]; } return ans + 1 } 首先树状数组c[i]里…

区间的关系的计数 HDU 4638 离线+树状数组

题目大意:给你n个人,每个人都有一个id,有m个询问,每次询问一个区间[l,r],问该区间内部有多少的id是连续的(单独的也算是一个) 思路:做了那么多离线+树状数组的题目,感觉这种东西就是一个模板了,23333,反正都是定义右区间的. 这题的关键难度就是如何定义id是连续的呢.我们每次往区间里面放一个数值以后都要add(pos, 1),就是把pos~n的所有的关系都+1.然后如果说在pos之前就出现id-1,就要add(pos[id-1], -1)(同理id+1也是这样),这样子表示从pos[…