HDOJ-1002】的更多相关文章

Problem Description I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.   Input The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines f…
A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 242959    Accepted Submission(s): 46863 Problem Description I have a very simple problem for you. Given two integers A and B, you…
A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 260585    Accepted Submission(s): 50389 Problem Description I have a very simple problem for you. Given two integers A and B, you…
A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 241933    Accepted Submission(s): 46646 Problem Description I have a very simple problem for you. Given two integers A and B, you…
先说一下Java对于ACM的一些优点吧: (1) 对于熟悉C/C++的程序员来说Java 并不难学,两周时间基本可以搞定一般的编程,再用些时间了解一下Java库就行了.Java的语法和C++非常类似,可以说是C++的升级版,只是更加强调面向对象思想而已.(个人见解...) (2) 在一般比赛中,Java程序会有额外的时间和空间,但真正进行大规模运算时Java并不比C/C++慢,输入输出效率比较低而已 (3) Java 代码简单且功能强大,有些像高精度之类的算法用Java实现起来更为简洁方便(AC…
题目传送门 /* 题意:在一个矩阵里放炮台,满足行列最多只有一个炮台,除非有墙(X)相隔,问最多能放多少个炮台 搜索(DFS):数据小,4 * 4可以用DFS,从(0,0)开始出发,往(n-1,n-1)左下角走,x = cnt / n; y = cnt % n; 更新坐标, 直到所有点走完为止,因为从左边走到右边,只要判断当前点左上方是否满足条件就可以了 注意:当前点不能放炮台的情况也要考虑 g[x][y] == 'o'; 的错误半天才检查出来:) */ #include <cstdio> #…
典型的数列反演题. 运用莫比乌斯反演的一个结论 $[n = 1] = \sum_{d | n} \mu(d)$,将表达式做如下转化: $$ ans = \sum_{i=1}^n \sum_{j=1}^i (\lfloor \frac{i-1}{j} \rfloor + 1) \sum_{d | i \land d | j} \mu(d) \\ = \sum_{d=1}^n \mu(d) \sum_{i=1}^{\lfloor \frac{n}{d} \rfloor} \sum_{j=1}^i (…
TIANKENG’s rice shop Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 212    Accepted Submission(s): 9 Problem Description TIANKENG managers a pan fried rice shop. There are n kinds of fried rice…
HDOJ 题目分类 //分类不是绝对的 //"*" 表示好题,需要多次回味 //"?"表示结论是正确的,但还停留在模块阶 段,需要理解,证明. //简单题看到就可以敲的 1000:    入门用: 1001:    用高斯求和公式要防溢出 1004:1012: 1013:    对9取余好了 1017:1021: 1027:    用STL中的next_permutation() 1029:1032:1037:1039:1040:1056:1064:1065: 10…
HDOJ 题目分类 /* * 一:简单题 */ 1000:    入门用:1001:    用高斯求和公式要防溢出1004:1012:1013:    对9取余好了1017:1021:1027:    用STL中的next_permutation()1029:1032:1037:1039:1040:1056:1064:1065:1076:    闰年 1084:1085:1089,1090,1091,1092,1093,1094, 1095, 1096:全是A+B1108:1157:1196:1…