写出一个函数 anagram(s, t) 判断两个字符串是否可以通过改变字母的顺序变成一样的字符串. 您在真实的面试中是否遇到过这个题?     样例 给出 s = "abcd",t="dcab",返回 true. 给出 s = "ab", t = "ab", 返回 true. 给出 s = "ab", t = "ac", 返回 false. 标签 字符串处理 解题: class Sol…

158-两个字符串是变位词 写出一个函数 anagram(s, t) 判断两个字符串是否可以通过改变字母的顺序变成一样的字符串. 说明 What is Anagram? Two strings are anagram if they can be the same after change the order of characters. 样例 给出 s = "abcd",t="dcab",返回 true. 给出 s = "ab", t = &q…

题目描述: 写出一个函数 anagram(s, t) 去判断两个字符串是否是颠倒字母顺序构成的 样例 给出 s="abcd",t="dcab",返回 true     public class Solution { /** * @param s: The first string * @param b: The second string * @return true or false */ public boolean anagram(String s, Stri…

// 判断两个单词是否互为变位词: 如果两个单词中的字母相同,并且每个字母出现的次数也相同, 那么这两个单词互为变位词 #include <stdio.h> #include <string.h> int is_anagram(char *s1, char *s2) // 判断两个数是否互为变位词, 若是返回1 { if(strlen(s1) != strlen(s2)) ; ] = {}; char *p; p = s1; while( *p != '\0' ) count[*p…

Time limit(ms): 1000 Memory limit(kb): 65535   Description 输入N和一个要查找的字符串,以下有N个字符串,我们需要找出其中的所有待查找字符串的变位词(例如eat,eta,aet就是变位词)按字典序列输出,并且输出总数目 Input 第一行:N(代表共有N个字符串属于被查找字符串) (N<=50) 第二行:待查找的字符串(不大于10个字符) 以下N行:被查找字符串(不大于10个字符)   Output 按字典序列输出在被查找字符串中待查找字…

Given an array of strings, group anagrams together. For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"], Return: [ ["ate", "eat","tea"], ["nat",…

写一个函数推断两个字符串是否是变位词. 变位词(anagrams)指的是组成两个单词的字符同样,但位置不同的单词.比方说, abbcd和abcdb就是一对变位词 这也是简单的题. 我们能够排序然后对照, 也能够直接统计字符出现的个数来推断.这里给出统计字符来推断的代码: bool isAnagram1(const string& vLeft, const string& vRight) { if (vLeft.size() != vRight.size()) return false; i…

Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100. The order of output does not matter.…

Input: s: "abab" p: "ab" Output: [0, 1, 2] Explanation: The substring with start index = 0 is "ab", which is an anagram of "ab". The substring with start index = 1 is "ba", which is an anagram of "ab&…

Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100. The order of output does not matter.…