UVA 1476 1476 - Error Curves 题目链接 题意:给几条下凹二次函数曲线.然后问[0,1000]全部位置中,每一个位置的值为曲线中最大值的值,问全部位置的最小值是多少 思路:三分法,因为都是下凹函数,所以全部曲线合并起来.仍然是一个下凹函数.满足单峰.用三分求极值 代码: #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using n…

Josephina is a clever girl and addicted to Machine Learning recently. She pays much attention to a method called Linear Discriminant Analysis, which has many interesting properties. In order to test the algorithm's efficiency, she collects many datas…

                                       Error Curves Josephina is a clever girl and addicted to Machine Learning recently. She pays much attention to a method called Linear Discriminant Analysis, which has many interesting properties.In order to test…

对x的坐标三分: #include<cstdio> #include<algorithm> #define maxn 10009 using namespace std; double a[maxn],b[maxn],c[maxn]; int n; double f(double x) { double ans=-999999999.0,t; ;i<n;i++) { t=a[i]*x*x+b[i]*x+c[i]; ans=max(ans,t); } return ans; }…

Problem Description Josephina is a clever girl and addicted to Machine Learning recently. She pays much attention to a method called Linear Discriminant Analysis, which has many interesting properties. In order to test the algorithm's efficiency, she…

题目链接 题意:“铁人三项”比赛中,需要选手在t km的路程里进行马拉松和骑自行车项目.现有n名选手,每位选手具有不同的跑步速度和骑车速度.其中第n位选手贿赂了裁判员,裁判员保证第n名选手一定会取得冠军.问当马拉松路程与自行车路程分别为多少时,第n名选手才能取得冠军. 输出冠军与第二名所差的秒数以及马拉松路程与自行车路程. 分析: 设马拉松路程为r时选手i的用时:f(r) = r/rv[i] + (t-r)/kv[i] = ((kv[i]-rv[i])*r + t*rv[i])/(kv[i]*r…

Error Curves Time Limit:3000MS    Memory Limit:0KB    64bit IO Format:%lld & %llu SubmitStatusPracticeUVALive 5009 Appoint description: Description Josephina is a clever girl and addicted to Machine Learning recently. She pays much attention to a met…

Error Curves Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1198    Accepted Submission(s): 460 Problem Description Josephina is a clever girl and addicted to Machine Learning recently. She pa…

题目传送门 /* 三分:凹(凸)函数求极值 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> using namespace std; ; const int INF = 0x3f3f3f3f; const double EPS = 0.0000000001; struct F { double a, b, c; }f[MAXN]; int n; dou…

Error Curves Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 6241    Accepted Submission(s): 2341 Problem Description Josephina is a clever girl and addicted to Machine Learning recently. Shepay…