Given k strings, find the longest common prefix (LCP).   Example For strings "ABCD", "ABEF" and "ACEF", the LCP is "A" For strings "ABCDEFG", "ABCEFG" and "ABCEFA", the LCP is "ABC…

14. Longest Common Prefix Write a function to find the longest common prefix string amongst an array of strings. 寻找一个数组中最长的公共前缀 例如["baaa","caaabbb","aaaa"]输出"aaa" 结题思路: 判断非空的情况在进行计算 取第一个字符串最为标杆进行对比,因为最终结果一定在第一位中 用第一…

  public class Solution { /** * @param strs: A list of strings * @return: The longest common prefix */ public String longestCommonPrefix(String[] strs) { // write your code here if(strs.length == 0){ return ""; } String prefix = strs[0]; int i =…

1.当strs为空,直接输出“” 2.当strs中含有“”,直接输出“” 3.strs[0]的最长长度由最短公共长度l决定(code line:15) class Solution: # @return a string def longestCommonPrefix(self, strs): if strs == []: return "" for i in range(1,len(strs)): l1 = len(strs[0]) l2 = len(strs[i]) if l1&g…

多串LCS很适合SA但是我要学SAM 对第一个串求SAM,然后把剩下的串在SAM上跑,也就是维护p和len,到一个点,如果有ch[p][c],就p=ch[p][c],len++,否则向fa找最下的有c[p][c]的p,然后len=dis[p]+1,p=ch[p][c],否则就p=root,len=0(这个len每到一个节点就更新这个节点的f) 然后注意到在parent树上,因为每个节点代表的right集合是儿子的并集,所以f[u]是可以更新f[fa[u]]的,所以从底向上更新一遍(注意先更新!!…

[Q13] Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, w…

题目简述: Write a function to find the longest common prefix string amongst an array of strings. 解题思路: class Solution: # @return a string def longestCommonPrefix(self, strs): if strs == []: return '' minl = 99999 for i in strs: if len(i) < minl: minl = l…

Write a function to find the longest common prefix string amongst an array of strings. 解题思路: 老实遍历即可,注意边界条件: JAVA实现: static public String longestCommonPrefix(String[] strs) { if (strs.length == 0) return ""; for (int i = 0; i < strs[0].length(…

题目: Write a function to find the longest common prefix string amongst an array of strings. 思路:求最长前缀子串,假设第一个字符串是最长前缀子串,采用增强for得到数组中每个字符串,分别与第一个字符串的同一位置进行比较,有一个字符串在该位置不一致,就返回. public class Solution { public String longestCommonPrefix(String[] strs) { i…

题目: Write a function to find the longest common prefix string amongst an array of strings. 代码: class Solution { public: string longestCommonPrefix(vector<string>& strs) { ) return ""; std::]; ; i < strs.size(); ++i ) { size_t j = ;…