1093 Count PAT's (25 分) The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters. Now given any string, you are s…

The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters. Now given any string, you are supposed to tell the numb…

The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters. Now given any string, you are supposed to tell the numb…

本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/93389073 1093 Count PAT's (25 分)   The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed…

http://www.patest.cn/contests/pat-a-practise/1093 The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters. Now g…

The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters. Now given any string, you are supposed to tell the numb…

1093 字符串A+B (20 分) 给定两个字符串 A 和 B,本题要求你输出 A+B,即两个字符串的并集.要求先输出 A,再输出 B,但重复的字符必须被剔除. 输入格式: 输入在两行中分别给出 A 和 B,均为长度不超过 10​6​​的.由可见 ASCII 字符 (即码值为32~126)和空格组成的.由回车标识结束的非空字符串. 输出格式: 在一行中输出题面要求的 A 和 B 的和. 输入样例: This is a sample test to show you_How it works 输…

The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters. Now given any string, you are supposed to tell the numb…

如题,统计PAT出现的个数,注意PAT不一定要相邻,看题目给的例子就知道了. num1代表目前为止P出现的个数,num12代表目前为止PA出现的个数,num123代表目前为止PAT出现的个数. 遇到P,num1++. 遇到A,那么PA的个数为:前面统计的PA的个数(num12)+前面的P与当前A组成的个数(num1) 遇到T,那么PAT的个数为:前面统计的PAT的个数(num123)+前面的PA与当前的T组成的个数(num12) #include <iostream> #include <…

The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters. Now given any string, you are supposed to tell the numb…