原题目:Search for a Range, 现在题目改为: 34. Find First and Last Position of Element in Sorted Array Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity…

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1].…

leetcode - 34. Search for a Range - Medium descrition Given an array of integers sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the ta…

本人编程小白,如果有写的不对.或者能更完善的地方请个位批评指正! 这个是leetcode的第34题,这道题的tag是数组,需要用到二分搜索法来解答 34. Find First and Last Position of Element in Sorted Array Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target v…

乘风破浪:LeetCode真题_034_Find First and Last Position of Element in Sorted Array 一.前言 这次我们还是要改造二分搜索,但是想法却有一点不一样. 二.Find First and Last Position of Element in Sorted Array 2.1 问题 2.2 分析与解决 查找问题,时间复杂度要求对数级别的,我们自然的想到了二分查找,和上一题一样,需求都是有点不一样的,这次是有重复的数字,找出某一特定的重…

目录 题目链接 注意点 解法 小结 题目链接 Find First and Last Position of Element in Sorted Array - LeetCode 注意点 nums可能为空 时间复杂度为O(logn) 解法 解法一:最普通的二分搜索,先找到一个target,然后向两边拓展. class Solution { public: int binarySearch(vector<int>& nums, int target) { int left = 0,rig…

一.题目说明 题目是34. Find First and Last Position of Element in Sorted Array,查找一个给定值的起止位置,时间复杂度要求是Olog(n).题目的难度是Medium! 二.我的解答 这个题目还是二分查找(折半查找),稍微变化一下.target==nums[mid]后,需要找前面.后面的值是否=target. 一次写出来,bug free,熟能生巧!怎一个爽字了得! #include<iostream> #include<vecto…

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous ro…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

https://leetcode.com/problems/search-for-a-range/ Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the…

Search for a Range Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For ex…

1 题目: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given […

Description Given a sorted array of n integers, find the starting and ending position of a given target value. If the target is not found in the array, return [-1, -1]. Example Given [5, 7, 7, 8, 8, 10] and target value 8,return [3, 4]. Challenge O(l…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target , -]. For example, Given [, , , , , ] and target value , , ]. Analysi…

Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example,Given [5, 7,…

Given an array of integers sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For e…

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1].…

题目链接: https://leetcode.com/problems/search-for-a-range/?tab=Description   Problem: 在已知递减排序的数组中,查找到给定数字的起止下标   采用两遍扫描: 第一遍扫描得到给定数字的起始下标,(从下标i==0开始到nums.lenght-1) 第二遍扫描从第一遍扫描得到的下标开始进行扫描    参考代码: package leetcode_50; /*** * * @author pengfei_zheng * 数组中…

题目描述: Given a sorted array of integers, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. For example, Given…

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1].…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 二分查找 日期 题目地址:https://leetcode.com/problems/find-first-and-last-position-of-element-in-sorted-array/description/ 题目描述 Given an array of integers nums sorted in ascending order,…

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1].…

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1].…

思路:先二分查找到一个和target相同的元素,然后再左边二分查找左边界,右边二分查找有边界. class Solution { public: , end = -; int ends; int lSearch(int left, int right, vector<int>& nums, int target) { ; ; if(nums[mid] == target){ || (mid > && nums[mid - ] < target)) retur…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4970 访问. 给定一个按照升序排列的整数数组 nums,和一个目标值 target.找出给定目标值在数组中的开始位置和结束位置. 你的算法时间复杂度必须是 O(log n) 级别. 如果数组中不存在目标值,返回 [-1, -1]. 输入: nums = [5,7,7,8,8,10], target = 8 输出: [3,4] 输入: nums = [5,7,7,…

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given targetvalue.Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. Ex…

题意懒得抄了,大概是:在升序数组中给定整数target,找到第一个和最后一个target的索引,找到返回{index1, index2},否则返回{-1, -1}: 时间复杂度要求:O(logn) 分析:要求对数时间,又是查找,我们不难想到二分查找.但是有一点,怎么查到第一个和最后一个呢?这困扰了我. 算法:来自leetcode caikehe 1. 使用二分变体,查找target作为index1,再找target+1, 作为index2: 2. 对index做判断,如果它未越界且它的对应值等于…

1. 原始题目 给定一个按照升序排列的整数数组 nums,和一个目标值 target.找出给定目标值在数组中的开始位置和结束位置. 你的算法时间复杂度必须是 O(log n) 级别. 如果数组中不存在目标值,返回 [-1, -1]. 示例 1: 输入: nums = [5,7,7,8,8,10], target = 8 输出: [3,4] 示例 2: 输入: nums = [5,7,7,8,8,10], target = 6 输出: [-1,-1] 2. 思路 既然是有序数组,可以2分法.如果存…

描述: Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -…

Given an array of integers nums sorted in ascending order, find the starting and ending position of a given targetvalue. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. E…