给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数.函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2.请注意,返回的下标值(index1 和 index2)不是从零开始的.你可以假设每个输入都只有一个解决方案,而且你不会重复使用相同的元素.输入:数组 = {2, 7, 11, 15}, 目标数 = 9输出:index1 = 1, index2 = 2详见:https://leetcode.com/problems/two-…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…

1. 原始题目 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数. 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2. 说明: 返回的下标值(index1 和 index2)不是从零开始的. 你可以假设每个输入只对应唯一的答案,而且你不可以重复使用相同的元素. 示例: 输入: numbers = [2, 7, 11, 15], target = 9 输出: [1,2] 解释: 2 与 7 之和等于目标数 9 .因此 in…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two numbers such that they add up to the target, where index1 mu…

Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: TrueExample 2: Input: 5 / \ 3 6 / \ \ 2 4…

Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4…

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 m…

给定一个二叉搜索树和一个目标结果,如果 BST 中存在两个元素且它们的和等于给定的目标结果,则返回 true. struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } }; class Solution { public: TreeNode* node; bool findTarget(TreeNo…

from typing import List# 这道题很容易能够想到,只需要遍历两边列表就可以了# 两层循环class Solution: def twoSum(self, numbers: List[int], target: int) -> List[int]: # 第一次遍历列表 for index1 in range(len(numbers)): # 注意这里,如果有重复的值可以直接跳过 if index1 != 0 and numbers[index1] == numbers[ind…

167. Two Sum II - Input array is sorted Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that t…