Two integers are called "friend numbers" if they share the same sum of their digits, and the sum is their "friend ID". For example, 123 and 51 are friend numbers since 1+2+3 = 5+1 = 6, and 6 is their friend ID. Given some numbers, you…

1120. Friend Numbers (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Two integers are called "friend numbers" if they share the same sum of their digits, and the sum is their "friend ID". For example, 123 and 5…

1069 The Black Hole of Numbers (20 分)   For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the seco…

1023 Have Fun with Numbers (20 分)   Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactl…

1069 The Black Hole of Numbers (20分) 1. 题目 2. 思路 把输入的数字作为字符串,调用排序算法,求最大最小 3. 注意点 输入的数字的范围是(0, 104), 如果作为字符串处理时要注意前面补0 4. 代码 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; bool cmp(char a, char b){ return a>…

1023 Have Fun with Numbers (20 分)   Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactl…

PAT (Advanced Level) Practice 1023 Have Fun with Numbers (20 分) 凌宸1642 题目描述: Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be…

题意: 输入一个不超过20位的正整数,问乘2以后是否和之前的数组排列相同(数字种类和出现的个数不变),输出Yes或No,并输出乘2后的数字. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; string s; ]; int main(){ cin>>s; int len=s.size(); ;i>=;--i) ++vis[s[i]-'…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6789775.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 水题,就是统计n个数的数位和有多少个不同的,并且输出即可. #include <iostream> #include <cstdio> #include <algorithm> #include <string> #in…

一.技术总结 这一题可以使用map进行想打印存储,因为数据量不是很大,最后直接输出.但是还是觉得没有必要. 主要考虑两个问题,首先是数字转化为字符串,实质就是进制转化,但是有点不同,如果十位有数字,个位是0,不用输出这个0.所以使用了条件判断if(t / 13 && t % 13) cout << " ",来看是否需要输出后一位,如果不是也就没必要输出这个空格了,然后用if(t % 13) cout << a[t%13];来输出个位. 然后是字符…