class Solution { public void printChoices(int[] A, int[][] C) { System.out.println("硬币列表如下:"); for(int i=0,l=A.length; i<l; i++) { System.out.print(A[i] + "\t"); } System.out.println(""); final int N = C.length; String[] n…

Resolving Cloud Save Conflicts IN THIS DOCUMENT Get Notified of Conflicts Handle the Simple Cases Design a Strategy for More Complex Cases First Attempt: Store Only the Total Second Attempt: Store the Total and the Delta Solution: Store the Sub-total…

Description There are n coins in a line. Two players take turns to take one or two coins from right side until there are no more coins left. The player who take the last coin wins. Could you please decide the first player will win or lose? If the fir…

Description There are n coins with different value in a line. Two players take turns to take one or two coins from left side until there are no more coins left. The player who take the coins with the most value wins. Could you please decide the first…

题目描述 Farmer John's cows like to play coin games so FJ has invented with a new two-player coin game called Xoinc for them. Initially a stack of N (5 <= N <= 2,000) coins sits on the ground; coin i from the top has integer value C_i (1 <= C_i <=…

题目描述 Farmer John's cows like to play coin games so FJ has invented with a new two-player coin game called Xoinc for them. Initially a stack of N (5 <= N <= 2,000) coins sits on the ground; coin i from the top has integer value C_i (1 <= C_i <=…

After hh has learned how to play Nim game, he begins to try another coin game which seems much easier. The game goes like this: Two players start the game with a circle of n coins. They take coins from the circle in turn and every time they could tak…

Coin Game Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 888    Accepted Submission(s): 547 Problem Description After hh has learned how to play Nim game, he begins to try another coin game whi…

https://daniu.luogu.org/problemnew/show/P2964 dp[i][j] 表示桌面上还剩i枚硬币时,上一次取走了j个的最大得分 枚举这一次要拿k个,转移到dp[i-k][k] dp[i][j]=max(sum[i]-dp[i-k][k]) 因为 上一次取走j个和取走j-1个 k的取值范围 只相差 2*j-1 和 2*j 所以 直接 dp[i][j]=dp[i][j-1] 然后k分别等于  2*j-1 和 2*j,转移 最后输出dp[n][1],因为先手可以拿1…

Problem Description After hh has learned how to play Nim game, he begins to try another coin game which seems much easier.The game goes like this: Two players start the game with a circle of n coins. They take coins from the circle in turn and every…