Add Again Summation of sequence of integers is always a common problem in Computer Science. Rather than computing blindly, some intelligent techniques make the task simpler. Here you have to find the summation of a sequence of integers. The sequence…
def counting_sort(array1, max_val): m = max_val + count = [] * m for a in array1: # count occurences count[a] += i = for a in range(m): for c in range(count[a]): array1[i] = a i += return array1 print(counting_sort( [, , , , , , , , , , ], ))…
先看下面一段代码: package 类集; import java.util.Set; import java.util.TreeSet; class Person{ private String name ; private int age ; public Person(String name,int age){ this.name = name ; this.age = age ; } public String gtoString(){ return "姓名:" + this.…
//定义一个100元素的集合,包含A-Z List<String> list = new LinkedList<>(); for (int i =0;i<100;i++){ list.add(String.valueOf((char)('A'+Math.random()*('Z'-'A'+1)))); } System.out.println(list); //统计集合重复元素出现次数,并且去重返回hashmap Map<String, Long> map = l…
Given a sorted array, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. Ex…
题目描述: Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Example 1: Input: [1,2,3,1] Outpu…
