给定一个只包括 '(',')','{','}','[',']' 的字符串,判断字符串是否有效.括号必须以正确的顺序关闭,"()" 和 "()[]{}" 是有效的但是 "(]" 和 "([)]" 不是.详见:https://leetcode.com/problems/valid-parentheses/description/ 实现语言:Java class Solution { public boolean isValid(S…

Valid Parentheses  Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]"…

题目描述:Valid Parentheses Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]&qu…

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]"…

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct…

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]"…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:有效,括号,括号匹配,栈,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/valid-parentheses/#/description 题目描述 Given a string contain…

Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]"…

题目在这里: https://leetcode.com/problems/valid-parentheses/ [标签]Stack; String [个人分析]这个题应该算是Stack的经典应用.先进后出 ( FILO) 的结构: 先来的左边括号跟后面的右边括号相匹配. [代码解释]创建一个栈,如果遇到的是 '{', '(', '[', 就压到栈里面去,留着跟后面遇到的后边括号匹配.如果遇到了'}', ']', ')',首先看看栈里面 是不是空,里面有没有匹配的部分. [一些心得]我在别人那儿看…

描述: 给定一些列括号,判断其有效性,即左括号有对应的有括号,括号种类只为小,中,大括号. 解决: 用栈. bool isValid(string s) { stack<char> st; for (auto i : s) { if (i == '(' || i == '[' || i == '{') { st.push(i); continue; } else { if (st.empty()) return false; char c = st.top(); if (i == ')' &a…