从网上查到的方法是 用get_object_vars 把类类型转换成数组 然后在用foreach  遍历即可 $array = get_object_vars($test); $json= '[{"id":"1","name":"\u5f20\u96ea\u6885","age":"27","subject":"\u8ba1\u7b97\u673a\u79d…

前台传到后台的json字符串 前台实现这种格式json字符串方式: function contentFun(){ respType = respTypeFun(); return "{\"respType\":\"" + respType + "\",\"content\":\"" + content + "\",\"name\":\""…

JArray jo = (JArray)JsonConvert.DeserializeObject("这里是json字符串");…

题目:把字符串嵌套关系转换成数组,字符串只包含成对中括号.数字和逗号字符串:(1,(1,2,(1,(1,2,(1)),3)),3,(1,(1,2,((1((1,(1,2,(1,2,3),4,5),3),2)),2)),((1,2,3),2,3),4,5),5) 程序: $string = '(1,(1,2,(1,(1,2,(1)),3)),3,(1,(1,2,((1,((1,(1,2,(1,2,3),4,5),3),2)),2)),((1,2,3),2,3),4,5),5)'; $result…

package com.xxxx.live.webapp.selvert; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.HashMap; import java.util.Map; import org.apac…

传入参数类型 {"aaa":"aaaa","bbb":"bbb","ccc":"ccc","waterMark":[{'name':'默认name1','position':'默认地址1'},{'name':'默认name2','position':'默认地址2'}] } 遍历 import java.io.BufferedReader; import java.io…

1.序列化为字符串 $("#Form").serialize();//name=zhangsan&sex=1&age=20   2.序列化为数组 var formData=$("#form").serializeArray();//[Object, Object, Object] 自定义参数补充 formData.push({"name": "psid", "value": $("…

json ={ GW:[{id:"655",mc:"董事"},{id:"656",mc:"书记"},{id:"804",mc:"经理"},{id:"818",mc:"财务总监"},{id:"820",mc:"助理"}], GZ:[{id:"1",mc:"电工"},{id…

1.JSON字符串与字典(Dictionary)之间的相互转换 import Foundation //JSON字符串转换为字典(Dictionary) func getDictionaryFromJSONString(_ jsonString:String) ->NSDictionary{ let jsonData:Data = jsonString.data(using: .utf8)! let dict = try? JSONSerialization.jsonObject(with: j…

无数据头Json字符串 Json字符串只有数组,而次数组没有名字,如下 [ { "name": "zhangsan", "age": "10", "phone": "11111", "email": "11111@11.com" }, { "name": "lisi", "age": &q…