203题是在链表中删除一个固定的值,83题是在链表中删除重复的数值,但要保留一个:82也是删除重复的数值,但重复的都删除,不保留. 比如[1.2.2.3],83题要求的结果是[1.2.3],82题要求的结果是[1,3]. 这种题用递归去做比较方便思考,特别是这种重复的数值.递归就是只遍历当前的节点的情况,之前的不用管,之后的以当前节点为出发点思考问题. 203. Remove Linked List Elements class Solution { public: ListNode* remo…
剑指 Offer 22. 链表中倒数第k个节点 题意 输入一个链表,输出该链表中倒数第k个节点.为了符合大多数人的习惯,本题从1开始计数,即链表的尾节点是倒数第1个节点. ​ 例如,一个链表有 6 个节点,从头节点开始,它们的值依次是 1.2.3.4.5.6,则这个链表的倒数第 3 个节点是值为 4 的节点. ​ 链表节点的定义如下: struct ListNode { int val; ListNode* next; ListNode(int x) : val(x), next(NULL) {…
237 - Delete Node in a Linked List Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked…
Question 203. Remove Linked List Elements Solution 题目大意:从链表中删除给定的数 思路:遍历链表,如果该节点的值等于给的数就删除该节点,注意首节点 Java实现: public ListNode removeElements(ListNode head, int val) { ListNode cur = head; while (cur != null) { if (cur.next != null && cur.next.val ==…
Remove Linked List Elements Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 --> 5 Credits:Special thanks to @mith…
Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6,  val = 6Return: 1 --> 2 --> 3 --> 4 –> 5 题目要求: 删除链表中包含val的元素结点 解题思路: 重点在于找到第一个非val的头结点,然后遍历链表,依次删除值为…
Remove Linked List Elements Remove all elements from a linked list of integers that have value *val*. Example: Input: 1->2->6->3->4->5->6, val = 6 Output: 1->2->3->4->5 解 /** * Definition for singly-linked list. * struct List…
203. Remove Linked List Elements[easy] Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 --> 5 Credits:Special than…
Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 --> 5 Credits:Special thanks to @mithmatt for adding this problem…
题意:移除链表中元素值为val的全部元素. 思路:算法复杂度肯定是O(n),那么就在追求更少代码和更少额外操作.我做不出来. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* removeElemen…