题目 Given a string, find the length of the longest substring without repeating characters. Example 1:  Input:"abcabcbb"   Output:3  Explanation:The answer is "abc",with the length of 3. Example 2:  Input:"bbbb"  Output:1  Expl…

Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst…

Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst…

Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 Explana…

题目: Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the answer is "b", with the length of…

Given a string, find the length of the longest substring without repeating characters.Examples:Given "abcabcbb", the answer is "abc", which the length is 3.Given "bbbbb", the answer is "b", with the length of 1.Give…

题意:给一字符串,求一个子串的长度,该子串满足所有字符都不重复.字符可能包含标点之类的,不仅仅是字母.按ASCII码算,就有2^8=128个. 思路:从左到右扫每个字符,判断该字符距离上一次出现的距离是多少,若大于max,则更新max.若小于,则不更新.每扫到一个字符就需要更新他的出现位置了.这里边还有个注意点,举例说明: 假如有长为16串 s="arbtbqwecpoiuyca" 当扫到第2个b时,距离上一个b的距离是2:(直接减) 当扫到第2个c时,距离上一个c的距离是6:(直接减…

Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest subst…

只遍历一次字符串即可求出最长不重复子串的长度. int lengthOfLongestSubstring(string s) { vector<,-); //记录字符上一次出现的位置,ASCII共有256个 ; //当前所在不重复子串的起始位置的上一个位置 ; ;i<s.size();i++) { if(charhash[s[i]]>start) //如果该字符在当前子串中出现过 start=charhash[s[i]]; //开始新的子串 charhash[s[i]]=i; //更新字…

Given a string, find the length of the longest substring without repeating characters. 来源:力扣(LeetCode)链接:https://leetcode-cn.com/problems/longest-substring-without-repeating-characters著作权归领扣网络所有.商业转载请联系官方授权,非商业转载请注明出处. 这道题目一拿到手,想都不用想,直接暴力遍历.然而结果虽然可行,…