String to Integer (atoi) Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended f…
这道题在LeetCode OJ上难道属于Easy.可是通过率却比較低,究其原因是须要考虑的情况比較低,非常少有人一遍过吧. [题目] Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the pos…
[LeetCode]397. Integer Replacement 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/integer-replacement/description/ 题目描述: Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you…
Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…
Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…
Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 数学解法 动态规划 日期 题目地址:https://leetcode.com/problems/integer-break/description/ 题目描述 Given a positive integer n, break it into the sum of at least two positive integers and maximize…
刚看到题就想用数组做,发现大多数解也是用数组做的,突然看到一个清新脱俗的解法: int atoi(const char *str) { ; int n; string s(str); istringstream iss(s); iss>>n; return n; } 代码简洁,核心使用的是istringstream C++串流输入类,该类对象能把字符串对象str读出字符并写入到自定义的各种类型变量中.…
题意:字符串转正数 原题来自:https://leetcode.com/problems/string-to-integer-atoi/ 分析: <程序员面试宝典>上出现的面试题,主要是考虑到细节. 1. 字串为空或者全是空格,返回0: 2. 字串的前缀空格需要忽略掉: 3. 忽略掉前缀空格后,遇到的第一个字符,如果是‘+’或‘-’号,继续往后读:如果是数字,则开始处理数字:如果不是前面的2种,返回0: 4. 处理数字的过程中,如果之后的字符非数字,就停止转换,返回当前值: 5. 在上述处理过…
class Solution(object): def myAtoi(self, str): """ :type str: str :rtype: int """ intMax=2147483647 intMin=-2147483648 str=str.strip() strLen = len(str) if strLen <= 0: return 0 bolNegative = False tmp = str[0] start=0 if…