题目代号:HDU 1711 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 28288 Accepted Submission(s): 11891 Problem Description Give…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 19246 Accepted Submission(s): 8267 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[…
Number Sequence Time Limit : 10000/5000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 90 Accepted Submission(s) : 57 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Given two sequences…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000…
Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1]…
白书说这个是MP,没有对f 数组优化过,所以说KMP有点不准确 #include <stdio.h> int a,b; int T[1000010],P[10010];//从0开始存 int f[10010];//记录P的自我匹配 void getFail(){ int m=b; f[0]=f[1]=0; for(int i=1;i<m;i++){ int j=f[i]; while(j&&P[i]!=P[j])j=f[j]; f[i+1]= P[i]==P[j] ? j…
HDU 1711 Number Sequence(数列) Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) [Description] [题目描述] Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N…
HDU 1005 Number Sequence(数列) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) [Description] [题目描述] A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, an…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 40053 Accepted Submission(s): 16510 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 39408 Accepted Submission(s): 16269 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 40388 Accepted Submission(s): 16659 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
HDU - 1711 A - Number Sequence Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... ,…
原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1005 主要内容: A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). 看到这样的公式很容易想到递归调用求解,但是在本题中n的取…
Number Sequence Time Limit: 10000/3000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 895 Accepted Submission(s): 374 Problem Description Given a number sequence b1,b2…bn.Please count how many number sequences a1,a2,..…
Number Sequence Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 16532 Accepted Submission(s): 7283 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…
Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 85249 Accepted Submission(s): 20209 Problem Description A number sequence…
题目链接 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test ca…
Description There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules: ● a i ∈ [0,n] ● a i ≠ a j( i ≠ j ) For sequence a and sequence b, the integrating degree t is defined as follows(“�” denotes exclus…
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 177761 Accepted Submission(s): 44124 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B…
我的第一道KMP. 把两个数列分别当成KMP算法中的模式串和目标串,这道题就变成了一个KMP算法模板题. #include<stdio.h> #include<string.h> #define N 1000005 #define M 10005 int a[N],b[M]; int next[M]; int n,m; void setNext() { int i,j; i=0; j=-1; next[i]=j; while(i<m) { if(j==-1||b[i]==b[…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 题目大意:给你两个数字数组a和b,若b是a的子序列则输出b在a中第一次出现的位置,否则输出-1.解题思路:直接套模板即可. 代码: #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ; int n,m; int nxt…
Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1] = b[M]. If there are…
传送门 题目大意:b在a第一次出现的位置 题解:KMP 代码: #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #define N 1000008 #define M 10009 using namespace std; int T; int a[N],b[M]; int nxt[M]; int lena,lenb; void getnext() { mems…
Least Cost Bracket Sequence(贪心) Describe This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequenc…
