771. Jewels and Stones (Easy)# You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also…
problem 938. Range Sum of BST 参考 1. Leetcode_easy_938. Range Sum of BST; 完…
又是一道有意思的题目,Count of Range Sum.(PS:leetcode 我已经做了 190 道,欢迎围观全部题解 https://github.com/hanzichi/leetcode) 题意非常简单,给一个数组,如果该数组的一个子数组,元素之和大于等于给定的一个参数值(lower),小于等于一个给定的参数值(upper),那么这为一组解,求总共有几组解. 一个非常容易想到的解法是两层 for 循环遍历子数组首尾,加起来判断,时间复杂度 O(n^2). /** * @param…
https://leetcode.com/problems/count-of-range-sum/ Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive. Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), incl…
Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive.Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive. Note:A naive algorithm of O(n2) is trivial.…
303. Range Sum Query - Immutable class NumArray { private: vector<int> v; public: NumArray(vector<int> &nums) { int n = nums.size(); v = vector<int>(n + 1); int sum = 0; for (int i = 1; i <= n; ++i) { sum += nums[i - 1]; v[i] = su…
题目 Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). Range Sum Query 2D The above rectangle (with the red border) is defined by (row1, col1)…
1.原题: https://leetcode.com/problems/range-sum-of-bst/ Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Input: root =…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/contest/weekly-contest-110/problems/range-sum-of-bst/ 题目描述 Given the root node of a binary search tree, return the sum of values of all nodes wi…
这是悦乐书的第359次更新,第386篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第221题(顺位题号是938).给定二叉搜索树的根节点,返回节点值在[L,R]之间的所有节点的值的总和.二叉搜索树的节点值唯一.例如: 输入:root = [10,5,15,3,7,null,18],L = 7,R = 15 输出:32 输入:root = [10,5,15,3,7,13,18,1,null,6],L = 6,R = 10 输出:23 注意: 树中的节点数最多为1000…