本场比赛的三个水题之一,题意是两个玩家每人都持有一手牌,问第一个玩家是否有一种出牌方法使得在第一回和对方无牌可出.直接模拟即可,注意一次出完的情况,一开始没主意,wa了一发. #include<cstdio> #include<string> #include<cstring> #include<iostream> #include<algorithm> using namespace std; char s[3][30]; int player…

Turn the pokers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 108    Accepted Submission(s): 21 Problem Description During summer vacation,Alice stay at home for a long time, with nothing to…

The sum of gcd Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 23    Accepted Submission(s): 4 Problem Description You have an array A,the length of A is n Let f(l,r)=∑ri=l∑rj=igcd(ai,ai+1....a…

构造题: 比赛的时候只想到:前面一样的数,后面 是类似1,2,3,4,5,6....t这 既是:t+1,t+1...,1,2,3,...t t+1的数目 可能 很多, 题解时YY出一个N 然后对N  判断. seg{Li*(Li-1)} = n*n+n-2*k=d; 每次跑sqrt(n)找到 最近的 d ,D_new=d-Li*(Li-1); 这样一定能解的:d 一定是偶数,Li*(Li-1)也一定是偶数,2*1=2; 还有seg(Li)=n; 当Li=1是 Li*Li-Li=0; 加入一些1就…

First One Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 142    Accepted Submission(s): 37 Problem Description soda has an integer array a1,a2,-,an. Let S(i,j) be the sum of ai,ai+1,-,aj. No…

In Touch Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 67    Accepted Submission(s): 11 Problem Description There are n soda living in a straight line. soda are numbered by 1,2,-,n from lef…

pid=5358">HDU 5358 题意: 求∑​i=1​n​​∑​j=i​n​​(⌊log​2​​S(i,j)⌋+1)∗(i+j). 思路: S(i,j) < 10^10 < 2^34.所以log2(S)+1的值仅仅可能在1~35之间.因为log变化缓慢的函数特性,我们能够S(i,n)分作多个同样log值的区间来计算,用pos[i][j]预处理记录每一个以i为起点,log(s)值为j的区间的右边界.就可以优化至nlogn的复杂度. 主要是写起来比較难一些,一些细节比較纠结,…

I Wanna Become A 24-Point Master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 60    Accepted Submission(s): 16 Special Judge Problem Description Recently Rikka falls in love with an old but…

Buildings Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 185    Accepted Submission(s): 25 Problem Description Your current task is to make a ground plan for a residential building located i…

pid=5371">HDU 5371 题意: 定义一个序列为N序列:这个序列按分作三部分,第一部分与第三部分同样,第一部分与第二部分对称. 如今给你一个长为n(n<10^5)的序列,求出该序列中N序列的最大长度. 思路: 来自官方题解:修正了一些题解错别字(误 先用求回文串的Manacher算法.求出以第i个点为中心的回文串长度.记录到数组p中 要满足题目所要求的内容.须要使得两个相邻的回文串,共享中间的一部分,也就是说.左边的回文串长度的一半,要大于等于共享部分的长度,右边回文串也…