Number Transformation 我们能发现这个东西是以2 - k的lcm作为一个循环节, 然后bfs就好啦. #include<bits/stdc++.h> #define LL long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int,…

题意及思路:https://blog.csdn.net/bossup/article/details/37076965 代码: #include <bits/stdc++.h> #define LL long long #define INF 1e18 using namespace std; int lcm(int x, int y) { return x * y / __gcd(x, y); } const int maxn = 500010; LL a, b, k; LL dp[maxn…

Number Transformation II 题解: 对于操作2来说, a - a % x[i] 就会到左边离a最近的x[i]的倍数. 也就是说 [ k * x[i] + 1,  (k+1)* x[i] -1 ]这段区间的的数都会走到 k * x[i]上. 所以对于每个位置都先计算出他到右边最远的覆盖位置. 然后在反着求出每个位置能往左走走到的最远的位置. 代码: #include<bits/stdc++.h> using namespace std; #define Fopen freo…

题目链接:点击打开链接 = = 990+ms卡过 #include<stdio.h> #include<iostream> #include<string.h> #include<algorithm> #include<vector> #include<set> using namespace std; #define N 100010 #define L(x) (x<<1) #define R(x) (x<<…

题意及思路:https://www.cnblogs.com/liuzhanshan/p/6560499.html 这个做法的复杂度看似是O(n ^ 2),实际上均摊是O(n)的.我们考虑两种极端数据:一种是全是2,那么去重后实际上只有一个数.这样是O(n)的.另一种是所有的数都不一样,那么为了让最大的那个最小,数分别为2, 3 ...1e5, 1e5 + 1, 但是a和b之差最多只有1e6,这种情况甚至比刚才那种耗时更少.故复杂度均摊是O(n)的. 代码: #include <bits/stdc…

2014多校 第八题 1008 2014 Multi-University Training Contest 8 4952 Number Transformation Number Transformation Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 85 Accepted Submission(s): 31 Problem Descr…

3858: Number Transformation Time Limit: 1 Sec  Memory Limit: 64 MBSubmit: 82  Solved: 41[Submit][Status] Description Teacher Mai has an integer x. He does the following operations k times. In the i-th operation, x becomes the least integer no less th…

http://acm.hdu.edu.cn/showproblem.php?pid=4952 Number Transformation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 171    Accepted Submission(s): 69 Problem Description Teacher Mai has an inte…

题目链接:Codeforces 486C Palindrome Transformation 题目大意:给定一个字符串,长度N.指针位置P,问说最少花多少步将字符串变成回文串. 解题思路:事实上仅仅要是对称位置不同样的.那么指针肯定要先移动到这里,改动字符仅仅须要考虑两种方向哪种更优即 可. 然后将全部须要到达的位置跳出来.贪心处理. #include <cstdio> #include <cstring> #include <cstdlib> #include <…

C. Number Transformation II time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given a sequence of positive integers x1, x2, ..., xn and two non-negative integers a and b. Your task is…