No code is the best way to write secure and reliable applications. Write nothing; deploy nowhere.…

BACKGROUND Erasable memories may have erasable elements that can become unreliable after a predetermined number of erase cycles. Thus, if one cell is erased dramatically more than other cells, that cell may be prone to earlier failure than the rest o…

uva12545 Bits Equalizer You are given two non-empty strings S and T of equal lengths. S contains the characters `0', `1' and `?', whereas T contains `0' and `1' only. Your task is to convert S into T in minimum number of moves. In each move, you can…

“模拟”类型,题型容易,使用bitset库对二进制逐位操作,初始化.十进制转二进制(unsigned int).位操作. POJ - 3652 Persistent Bits Time Limit: 1000MS Memory Limit: 65536KB 64bit IO Format: %I64d & %I64u [Submit]   [Go Back]   [Status] Description WhatNext Software creates sequence generators …

In my last post I implement "Key Debounce" with port polling, port polling is not very efficient. And this time, I will use change notification instead of port polling. It generates interrupt and starts debounce when the level of digital port ch…

http://www.36dsj.com/archives/33650 http://flink.apache.org/news/2015/05/11/Juggling-with-Bits-and-Bytes.html http://www.bigsynapse.com/addressing-big-data-performance ,addressing-big-data-performance   第一篇描述,当前JVM存在的问题, 1. Java对象开销 Java对象的存储密度相对偏低,对…

主题链接: PKU:http://poj.org/problem?id=3652 ZJU:http://acm.zju.edu.cn/onlinejudge/showProblem.do? problemId=1933 HDU:http://acm.hdu.edu.cn/showproblem.php?pid=2721 Description WhatNext Software creates sequence generators that they hope will produce fai…

A New Change Problem Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 533    Accepted Submission(s): 265 Problem Description Now given two kinds of coins A and B,which satisfy that GCD(A,B)=1.Her…

解:略一思索:网络流啊!(别问我是怎么想到的......) 发现跟志愿者招募有点像.于是把图建一下,在下面开一条通道,但是每个点又都要经过,这时我们就无脑上下界一波. 通道向点连边,有费用.每个点向它下一次出现的点连边,费用0.每个点还向通道连边,费用0. 上下界费用流跑一下就出来费用了.然后是输出方案,看哪些边有流量,直接模拟. #include <bits/stdc++.h> , INF = 0x3f3f3f3f; struct Edge { int nex, v, c, len; Edg…

Change 题目背景 SOURCE:NOIP2015-SHY-10 题目描述 Alice 和 Bob 又聚在一起了!他们已经厌倦了取石子游戏,现在他们热衷于切题.于是,Alice 找到了一道题让 Bob 做.Alice 有一张 N*M 的表格,每个格子上有一个值 a[i][j] (1≤i≤N,1≤j≤ M),Alice 将会给 Bob 若干个操作,操作分以下三类: 1. 交换两行 2. 交换两列 3. 输出某一个格子上的值 由于 Bob 正在为给 Alice 出题而发愁,他请你完成这个题. 输…