466. Count The Repetitions】的更多相关文章

Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…
Leetcode 466 直接给出DP方程 dp[i][k]=dp[i][k-1]+dp[(i+dp[i][k-1])%len1][k-1]; dp[i][k]表示从字符串s1的第i位开始匹配2^k个s2串需要的长度 最后通过一个循环 累积最多可以匹配多少个s2串 除以n2下取整就是答案 用倍增加速后 总的复杂度nlogn 而本题的n非常小 轻松AC 体会到倍增的魅力了吧. const int maxn=100+1,INF=1e+9; long long int dp[maxn][30]; cl…
Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…
https://leetcode.com/problems/count-the-repetitions/description/ 找循环节 https://www.cnblogs.com/grandyang/p/6149294.html…
题意 5702 Count The Repetitions 0x50「动态规划」例题 描述 定义 conn(s,n) 为 n 个字符串 s 首尾相接形成的字符串,例如: conn("abc",2)="abcabc" 称字符串 a 能由字符串 b 生成,当且仅当从字符串 b 中删除某些字符后可以得到字符串 a.例如"abdbec"可以生成"abc",但是"acbbe"不能生成"abc".…
Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…
Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3]="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such tha…
Count how many nodes in a linked list. Example Given 1->3->5, return 3. 解法一: /** * Definition of ListNode * class ListNode { * public: * int val; * ListNode *next; * ListNode(int val) { * this->val = val; * this->next = NULL; * } * } */ class…
Define S = [s,n] as the string S which consists of n connected strings s. For example, ["abc", 3] ="abcabcabc". On the other hand, we define that string s1 can be obtained from string s2 if we can remove some characters from s2 such th…
http://contest-hunter.org:83/contest/0x50%E3%80%8C%E5%8A%A8%E6%80%81%E8%A7%84%E5%88%92%E3%80%8D%E4%BE%8B%E9%A2%98/5702%20Count%20The%20Repetitions 给两个串,第一个循环写$n1$次,求第二个最多可以循环写多少次使得其能与第一个循环串非连续匹配.$s \leqslant 100,n \leqslant 10^6$ 这个博客貌似鸽了许久了.. 可以想到朴素…