Pangu and Stones HihoCoder - 1636 题意 给你\(n\)堆石子,每次只能合成\(x\)堆石子\((x\in[L, R])\),问把所有石子合成一堆的最小花费. 思路 和合石子的那题很像,多加了的一个限制,所有我们可以想到要多开一维数组来计算. \(dp[i][j][x]:\)表示区间\([i, j]\)的范围内有\(x\)堆石子. 然后我们要分成两类讨论(\(sum[i]\)表示前\(i\)堆石子的和) \(1\).\(dp[i][j][1] = min(dp[i…

题意:有n堆石头,盘古每次可以选择连续的x堆合并,所需时间为x堆石头的数量之和,x∈[l,r],现在要求,能否将石头合并成一堆,如果能,最短时间是多少. 思路:(参考了ACM算法日常)DP[i][j][k],表示当前状态下[i,j]这个区间分成了k堆. 状态转移:1.k=1时,dp[i][j][k]=min(dp[i][j][D]+num[j]-num[i-1]),其中D∈[l,r], 2.k!=1时,dp[i][j][k]=min(dp[i][z][1]+dp[z+1][j][k-1]),(合…

#1636 : Pangu and Stones 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 In Chinese mythology, Pangu is the first living being and the creator of the sky and the earth. He woke up from an egg and split the egg into two parts: the sky and the earth. At the begi…

hihoCoder 1636 Pangu and Stones 思路:区间dp. 状态:dp[i][j][k]表示i到j区间合并成k堆石子所需的最小花费. 初始状态:dp[i][j][j-i+1]=0 状态转移: 如果k等于1,dp[i][j][1]=min(dp[i][j][1],dp[i][k][s-1]+dp[k+1][j][1]+sum[j]-sum[i-1])(i<=k<j) s从l到r,因为合并成一堆的时候是有堆数限制的 如果k大于1,dp[i][j][k]=min(dp[i][j…

Pangu and Stones 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 In Chinese mythology, Pangu is the first living being and the creator of the sky and the earth. He woke up from an egg and split the egg into two parts: the sky and the earth. At the beginning, t…

#1636 : Pangu and Stones 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 In Chinese mythology, Pangu is the first living being and the creator of the sky and the earth. He woke up from an egg and split the egg into two parts: the sky and the earth. At the begi…

#1636 : Pangu and Stones 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 In Chinese mythology, Pangu is the first living being and the creator of the sky and the earth. He woke up from an egg and split the egg into two parts: the sky and the earth. At the begi…

#1636 : Pangu and Stones 时间限制:1000ms 单点时限:1000ms 内存限制:256MB 描述 In Chinese mythology, Pangu is the first living being and the creator of the sky and the earth. He woke up from an egg and split the egg into two parts: the sky and the earth. At the begi…

/** 题目:hihoCoder #1320 : 压缩字符串 链接:https://hihocoder.com/problemset/problem/1320 描述 小Hi希望压缩一个只包含大写字母'A'-'Z'的字符串.他使用的方法是:如果某个子串 S 连续出现了 X 次,就用'X(S)'来表示. 例如AAAAAAAAAABABABCCD可以用10(A)2(BA)B2(C)D表示. 此外,这种压缩方法是可以嵌套的,例如HIHOHIHOCODERHIHOHIHOCODER可以表示成2(2(HIH…

2021.07.17 P4170 染色(区间DP) [P4170 CQOI2007]涂色 - 洛谷 | 计算机科学教育新生态 (luogu.com.cn) 重点: 1.目标状态可以由哪些状态转移过来. 题目: 每次可以改变一段连续区间的颜色,问最少需要几次可以吧颜色改为目标区间颜色. 分析: 在一段连续区间(l,r)内,如果l,r处颜色相同,则选择(l+1,r)以及(l,r-1)这两个区间内修改次数少的,如果不同,枚举区间内断点,将两个小区间内次数相加. 代码如下: #include<bits/…