#include<stdio.h> int main() { int i; ]; while(gets(a)!=NULL) { ;a[i]!='\0';i++) if('A'<=a[i]&&a[i]<='Z') a[i]='Z'-a[i]+'A'; puts(a); } ; }…

Problem F: 合唱比赛开始了! Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 440  Solved: 201[Submit][Status][Web Board] Description 为迎接计算机科技文化节的到来,我院面向一年级学生举办了一场合唱比赛.邀请了若干位专家担任评委,并为每个参赛队评分.现在,请设计一个程序来展示这个比赛过程. 其中,类 Team描述了参赛队的信息,包括:专业名称.每个专家给该参赛队的评分以及最终得分等.类C…

Problem F Time Limit : 3000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 54   Accepted Submission(s) : 6 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description 在网络课程上,我学到了很多有关IP的知识.IP全称叫网际…

Home Web Board ProblemSet Standing Status Statistics   Problem F: 求平均年龄 Problem F: 求平均年龄 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 720  Solved: 394[Submit][Status][Web Board] Description 定义一个Persons类,用于保存若干个人的姓名(string类型)和年龄(int类型),定义其方法 void ad…

Problem F Funny Car Racing There is a funny car racing in a city with n junctions and m directed roads. The funny part is: each road is open and closed periodically. Each road is associate with two integers (a, b), that means the road will be open fo…

Problem F. Door LockTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100500/attachments Description It was a beautiful night at Yekaterinburg, the sky was crystal clear with no clouds, and the view of the moon and the stars was…

Problem F "Folding" Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100002 Description Bill is trying to compactly represent sequences of capital alphabetic characters from 'A' to 'Z' by folding repeating subsequences insid…

Problem F. Fibonacci SystemTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=86821#problem/B Description Little John studies numeral systems. After learning all about fixed-base systems, he became inte…

最初的密码程序是在Hirst First c里面看到的,大概内容如下:对待加密的字符串的每一个字符和某个数值进行一次按位异或得到密文,再进行一次按位异或得到明文. 补充知识:按位异或的结果是“同位得1,异位得0”.比如数值2和数值1进行按位异或的情况如下:2对应的二进制表示:101对应的二进制表示:012^1的结果最终表示:00 这个时候再把2^1的结果和1进行按位异或010010 原文的加密程序如下: #include<stdio.h> //加密解密程序 void encrypt(char…

Problem F: ExponentiationTime Limit: 1 Sec Memory Limit: 128 MBSubmit: 4 Solved: 2[Submit][Status][Web Board] [Edit] [TestData]DescriptionProblems involving the computation of exact values of very large magnitude and precision are common. For example…