B - ACboy needs your help Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Description ACboy has N courses this term, and he plans to spend at most M days on study.Of course,the profit he will gain from diffe…
Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bowling-pin-like triangle like this: 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5 Then the other cows traverse…
题意 给一个字符串,只由数字组成,若是'1'-'26',则认为可以转换为'a'-'z'对应的字母,问有多少种转换方法. 题解 状态转移很好想,注意dp多开一位,dp[0]为dp[2]的计算做准备.dp[i]表示到索引为i-1的字符(含)为止转换方法数. 代码 public class Main { public static void main(String args[]) { String str="01"; System.out.print(transMeans(str)); }…
1.直接用递归函数计算状态转移方程,效率十分低下,可以考虑用递推方法,其实就是“正着推导,逆着计算” #include<iostream> #include<algorithm> using namespace std; #define maxn 1000+5 int n; int a[maxn][maxn]; int d[maxn][maxn]; int main(){ for(;cin>>n && n;){ memset(d,,sizeof(d));…
递归方法解决数塔问题 状态转移方程:d[i][j]=a[i][j]+max{d[i+1][j],d[i+1][j+1]} 注意:1\d[i][j]表示从i,j出发的最大总和;2\变界值设为0;3\递归变界为n;4\结果为d[1][1] #include<iostream> #include<algorithm> using namespace std; #define maxn 1000+5 int n; int a[maxn][maxn]; int d[maxn][maxn];…
