UVa 11524:In-Circle(解析几何)】的更多相关文章

Problem EIn-CircleInput: Standard Input Output: Standard Output In-circle of a triangle is the circle that touches all the three sides of the triangle internally. The center of the in-circle of a triangle happens to be the common intersection point o…
推公式 #include <cstdio> #include <cmath> double Cal( double a, double b, double c ) { return a + b - c; } int main() { int T; scanf( "%d", &T ); while ( T-- ) { ], n[], r; scanf( "%lf", &r ); ; i < ; ++i ) scanf( &…
题意:三角形ABC的内切圆把它的三边分别划分成 m1:n1,m2:n2 和 m3:n3 的比例.另外已知内切圆的半径 r ,求三角形ABC 的面积. #include<iostream> #include<iomanip> #include<algorithm> #include<cmath> #define sqr(a) (a)*(a) #define eps 1e-12 #define min(a,b) a<b?a:b #define max(a,…
//第一期 计算几何题的特点与做题要领: 1.大部分不会很难,少部分题目思路很巧妙 2.做计算几何题目,模板很重要,模板必须高度可靠. 3.要注意代码的组织,因为计算几何的题目很容易上两百行代码,里面大部分是模板.如果代码一片混乱,那么会严重影响做题正确率. 4.注意精度控制. 5.能用整数的地方尽量用整数,要想到扩大数据的方法(扩大一倍,或扩大sqrt2).因为整数不用考虑浮点误差,而且运算比浮点快. 一.点,线,面,形基本关系,点积叉积的理解 POJ 2318 TOYS(推荐) http:/…
题目链接:uva 1463 - Largest Empty Circle on a Segment 二分半径,对于每一个半径,用三分求出线段到线段的最短距离,依据最短距离能够确定当前R下每条线段在[0,L]上的可行区间,存在一个点被可行区间覆盖n次. #include <cstdio> #include <cstring> #include <cmath> #include <vector> #include <algorithm> using…
1.LA 5694 Adding New Machine 关键词:数据结构,线段树,扫描线(FIFO) #include <algorithm> #include <cstdio> #include <cstring> #include <string> #include <queue> #include <map> #include <set> #include <ctime> #include <cm…
Jump Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 1452 Integers 1, 2, 3,..., n are placed on a circle in the increasing order as in the following figure. We want to construct a sequence from these…
UVA - 524 Prime Ring Problem Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Description A ring is composed of n (even number) circles as shown in diagram. Put natural numbers  into each circle separately, and the sum of number…
1502: [NOI2005]月下柠檬树 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 1070  Solved: 596[Submit][Status][Discuss] Description Input 文件的第1行包含一个整数n和一个实数alpha,表示柠檬树的层数和月亮的光线与地面夹角(单位为弧度).第2行包含n+1个实数h0,h1,h2,…,hn,表示树离地的高度和每层的高度.第3行包含n个实数r1,r2,…,rn,表示柠檬树每层下底面的…
UVA 1394 And Then There Was One / Gym 101415A And Then There Was One / UVAlive 3882 And Then There Was One / POJ 3517 And Then There Was One / Aizu 1275 And Then There Was One (动态规划,思维题) Description Let's play a stone removing game. Initially, n ston…