Kingdom of Black and White Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 3735    Accepted Submission(s): 1122 Problem Description In the Kingdom of Black and White (KBW), there are two kinds o…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5583 Kingdom of Black and White Time Limit: 2000/1000 MS (Java/Others)   Memory Limit: 65536/65536 K (Java/Others) Problem Description In the Kingdom of Black and White (KBW), there are two kinds of frog…

Kingdom of Black and White Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5583 Description In the Kingdom of Black and White (KBW), there are two kinds of frogs: black frog and white frog. Now N frogs are stand…

Problem Description In the Kingdom of Black and White (KBW), there are two kinds of frogs: black frog and white frog. Now N frogs are standing in a line, some of them are black, the others are white. The total strength of those frogs are calculated b…

Kingdom of Black and White Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 585    Accepted Submission(s): 193 Problem Description In the Kingdom of Black and White (KBW), there are two kinds of…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5583 一个01串,求修改一个位置,使得所有数均为0或1的子串长度的平方和最大.先分块,然后统计好原来的结果,每次更新块,更新最大值. #include <algorithm> #include <iostream> #include <iomanip> #include <cstring> #include <climits> #include &l…

http://acm.hdu.edu.cn/showproblem.php?pid=5583 题意: 给出一个01串,现在对这串进行分组,连续相同的就分为一组,如果该组内有x个数,那么就对答案贡献x*x,现在最多可以修改原串中的一个字符,问答案最大可以为多少. 思路:暴力求解. 一开始只需要预处理分块,计算出每一分块的个数,然后暴力处理一下即可,需要注意分块数为1的情况,此时左右两边都要合并起来. #include<iostream> #include<cstdio> #inclu…

Kingdom of Black and White                                                                                                            Time Limit: 2000/1000 MS (Java/Others)                                                                             …

5573 Binary Tree(构造) 题意:给你一个二叉树,根节点为1,子节点为父节点的2倍和2倍+1,从根节点开始依次向下走k层,问如何走使得将路径上的数进行加减最终结果得到n. 联想到二进制. 思路和这个差不多吧:http://blog.csdn.net/u013068502/article/details/50094561 #include <set> #include <queue> #include <cstdio> #include <vector…

Matlab expects images of type double to be in the 0..1 range and images that are uint8 in the 0..255 range. You can convert the range yourself (but change values in the process), do an explicit cast (and potentially loose precision) or instruct Matla…