【leetcode】Wildcard Matching】的更多相关文章

Wildcard Matching Implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partia…
Implement wildcard pattern matching with support for '?' and '*'. '?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). The function p…
[3]Longest Substring Without Repeating Characters (2019年1月22日,复习) [5]Longest Palindromic Substring (2019年1月22日,复习) [6]ZigZag Conversion (2019年1月22日,复习) [8]String to Integer (atoi) (2019年1月22日,复习) [10]Regular Expression Matching (2019年1月22日,复习) [12]In…
[10]Regular Expression Matching [17]Letter Combinations of a Phone Number [22]Generate Parentheses (2019年2月13日) 给了一个N,生成N对括号的所有情况的字符串. n = 3 [ "((()))", "(()())", "(())()", "()(())", "()()()" ] 题解:dfs生成. c…
[44]Wildcard Matching [45]Jump Game II (2018年11月28日,算法群衍生题) 题目背景和 55 一样的,问我能到达最后一个index的话,最少走几步. 题解: [55]Jump Game (2018年11月27日,算法群) 给了一个数组nums,nums[i] = k 代表站在第 i 个位置的情况下, 我最多能往前走 k 个单位.问我能不能到达最后一个 index. 题解:虽然是贪心分类,我还是用dp解了.dp[i] 代表我能不能到达第 i 个位置. c…
题目如下: 解题思路:本题和[leetcode]97. Interleaving String非常相似,同样可以采用动态规划的方法.记dp[i][j] = 1或者0 表示pattern[0:i]是否匹配string[0:j] ,如果pattern[i] == string[j] 或者 pattern[i] == '?',那么dp[i][j]  = dp[i-1][j-1]:如果pattern[i] = '*' 则复杂一些,因为'*'可以匹配s[j-1],s[j] 或者不匹配,因此只要满足其中任意…
[LeetCode]792. Number of Matching Subsequences 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/number-of-matching-subsequences/description/ 题目描述: Given string S and a dictionary of words words,…
[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…
Given an index k, return the kth row of the Pascal's triangle. For example, given k = 3, Return [1,3,3,1]. Note: Could you optimize your algorithm to use only O(k) extra space? 思路:最简单的方法就是依照[Leetcode]Pascal's Triangle 的方式自顶向下依次求解,但会造成空间的浪费.若仅仅用一个vect…
53. Maximum Subarray[leetcode] Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4],the contiguous subarray [4,-1,2,1] has the largest sum = 6. 挑…