problem 599. Minimum Index Sum of Two Lists 题意:给出两个字符串数组,找到坐标位置之和最小的相同的字符串. 计算两个的坐标之和,如果与最小坐标和sum相同,那么将这个字符串加入结果res中,如果比sum小,那么sum更新为这个较小值,然后将结果res清空并加入这个字符串. solution: class Solution { public: vector<string> findRestaurant(vector<string>&…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:找到公共元素再求索引和 方法二:索引求和,使用堆弹出最小元素 日期 题目地址:https://leetcode.com/problems/minimum-index-sum-of-two-lists/description/ 题目描述 Suppose Andy and Doris want to choose a restaurant for…

［抄题］: Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice ti…

题目描述 Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie…

题目: 假设 Andy 和 Doris 想在晚餐时选择一家餐厅,并且他们都有一个表示最喜爱餐厅的列表,每个餐厅的名字用字符串表示. Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. 你需要帮助他们用最少的索引和找出他们共同喜爱的餐厅.如果答案不止一个,则输出所有答案并且不考虑…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find out their common interest with the least list index sum. If there is a choice tie betw…

原题链接在这里:https://leetcode.com/problems/minimum-index-sum-of-two-lists/description/ 题目: Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings. You need to help them find…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3802 访问. 假设Andy和Doris想在晚餐时选择一家餐厅,并且他们都有一个表示最喜爱餐厅的列表,每个餐厅的名字用字符串表示. 你需要帮助他们用最少的索引和找出他们共同喜爱的餐厅. 如果答案不止一个,则输出所有答案并且不考虑顺序. 你可以假设总是存在一个答案. 输入: ["Shogun", "Tapioca Express", &…

这是悦乐书的第272次更新,第286篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第139题(顺位题号是599).假设Andy和Doris想要选择一家餐馆吃晚餐,他们都有一个最受欢迎的餐馆列表.你需要用最少的列表索引总和帮助他们找出他们的共同兴趣.如果答案之间存在选择关系,则输出所有答案并且没有顺序要求.你可以假设总有一个答案.例如: 输入: ["Shogun", "Tapioca Express", "Burger King…

1.题目描述 2.问题分析 直接是用hash table 解决问题 3.代码 vector<string> findRestaurant(vector<string>& list1, vector<string>& list2) { vector<string> result; map<string,int>m; ; i < list1.size() ; i++ ) { m.insert( std::pair<stri…

假设Andy和Doris想在晚餐时选择一家餐厅,并且他们都有一个表示最喜爱餐厅的列表,每个餐厅的名字用字符串表示. 你需要帮助他们用最少的索引和找出他们共同喜爱的餐厅. 如果答案不止一个,则输出所有答案并且不考虑顺序. 你可以假设总是存在一个答案. 示例 1: 输入: ["Shogun", "Tapioca Express", "Burger King", "KFC"] ["Piatti", "T…

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.You need to help them find out their common interest with the least list index sum. If there is a choice tie betwe…

Minimum Path Sum Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time.   动态规划即可,与Unique…

题目描述: 题目链接:64 Minimum Path Sum 问题是要求在一个全为正整数的 m X n 的矩阵中, 取一条从左上为起点, 走到右下为重点的路径, (前进方向只能向左或者向右),求一条所经过元素和最小的一条路径. 其实,题目已经给出了提示:, 动态规划应该是最直接的解法之一. 这边我们了解到, 问题中只允许走到的每个点右移或者下移,这就意味着从起点开始, 都有两种后继路径(最后一行和最后一列除外),以此类推, 得到所有路径,然后取其中路径和虽小的值,就可以得到结果了. 但是!我们仔…

Minimum Path Sum Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 还是DP问题,给定一个m*n的二…

之所以将这三道题放在一起,是因为这三道题非常类似. 1. Minimum Path Sum 题目链接 题目要求: Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or righ…

Minimum Path Sum Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. SOLUTION 1: 相当基础…

Unique Paths https://oj.leetcode.com/problems/unique-paths/ A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to rea…

Minimum Path Sum Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 解题思路: 典型的动态规划.开辟…

引言 二维动态规划中最常见的是棋盘型二维动态规划. 即 func(i, j) 往往只和 func(i-1, j-1), func(i-1, j) 以及 func(i, j-1) 有关 这种情况下,时间复杂度 O(n*n),空间复杂度往往可以优化为O(n) 例题  1 Minimum Path Sum  Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right whi…

Minimum Path Sum 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/minimum-path-sum/description/ Description Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its…

64. 最小路径和 64. Minimum Path Sum 题目描述 给定一个包含非负整数的 m x n 网格,请找出一条从左上角到右下角的路径,使得路径上的数字总和为最小. 说明: 每次只能向下或者向右移动一步. 每日一算法2019/5/23Day 20LeetCode64. Minimum Path Sum 示例: 输入: [ [1,3,1], [1,5,1], [4,2,1] ] 输出: 7 解释: 因为路径 1→3→1→1→1 的总和最小. Java 实现 略 相似题目 62. 不同路…

题目链接:1338: The minimum square sum Description Given a prime p(p<108), you are to find min{x2+y2}, where x and y belongs to positive integer, so that x2+y2=0 (mod p). 输入一个质数 p,你找出两个正整数 x 和 y 使得 (x2+y2) mod p = 0,且 x2+y2 最小. Input Every line is a p. No…

Leetcode之动态规划(DP)专题-64. 最小路径和(Minimum Path Sum) 给定一个包含非负整数的 m x n 网格,请找出一条从左上角到右下角的路径,使得路径上的数字总和为最小. 说明:每次只能向下或者向右移动一步. 示例: 输入: [   [1,3,1], [1,5,1], [4,2,1] ] 输出: 7 解释: 因为路径 1→3→1→1→1 的总和最小. 找从左上角0,0到右下角的最短路径. DP:我们每个点(x,y)都可以表示为dp[x][y] = max( grid…

一.题目说明 题目64. Minimum Path Sum,给一个m*n矩阵,每个元素的值非负,计算从左上角到右下角的最小路径和.难度是Medium! 二.我的解答 乍一看,这个是计算最短路径的,迪杰斯特拉或者弗洛伊德算法都可以.不用这么复杂,同上一个题目一样: 刷题62. Unique Paths() 不多啰嗦,直接代码,注释中有原理: #include<iostream> #include<vector> using namespace std; class Solution{…