HDU 3784 继续xxx定律 HDU 2578 Dating with girls(1) 做3748之前要先做xxx定律  对于一个数n,如果是偶数,就把n砍掉一半:如果是奇数,把n变成 3*n+ 1后砍掉一半,直到该数变为1为止. 当n为3时,我们在验证xxx定律的过程中会得到一个序列,3,5,8,4,2,1,将3称为关键数,5,8,4,2称为覆盖数.现在输入n个数字a[i],根据关键数与覆盖数的理论,我们只需要验证其中部分数就可以确定所有数满足xxx定律,输出输入的n个数中的关键数.如果…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2578 Dating with girls(1) Description Everyone in the HDU knows that the number of boys is larger than the number of girls. But now, every boy wants to date with pretty girls. The girls like to date with…

Dating with girls(1) Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2127    Accepted Submission(s): 730 Problem Description Everyone in the HDU knows that the number of boys is larger than the…

Dating with girls(1) Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3869    Accepted Submission(s): 1196 Problem Description Everyone in the HDU knows that the number of boys is larger than the…

Dating with girls(1) Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5709    Accepted Submission(s): 1855 Problem Description Everyone in the HDU knows that the number of boys is larger than the…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2579 Dating with girls(2) Description If you have solved the problem Dating with girls(1).I think you can solve this problem too.This problem is also about dating with girls. Now you are in a maze and th…

xxx定律 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4606    Accepted Submission(s): 3333 Problem Description 对于一个数n,如果是偶数,就把n砍掉一半:如果是奇数,把n变成 3*n+ 1后砍掉一半,直到该数变为1为止.请计算需要经过几步才能将n变到1,具体可见样例.   In…

Dating with girls(2) Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1812    Accepted Submission(s): 505 Problem Description If you have solved the problem Dating with girls(1).I think you can s…

继续xxx定律 HDU3784 先看这个题目:HDU3782 #include<iostream> #include<algorithm> #include<stdio.h> #include<string.h> using namespace std; int main() { int n,s; while(scanf("%d",&n)!=EOF) { ) break; s=; ) { ==) {n=n/;s++;} else…

时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:5502 解决:1351 题目描述:     当n为3时,我们在验证xxx定律的过程中会得到一个序列,3,5,8,4,2,1,将3称为关键数,5,8,4,2称为覆盖数.现在输入n个数字 a[i],根据关键数与覆盖数的理论,我们只需要验证其中部分数就可以确定所有数满足xxx定律,输出输入的n个数中的关键数.如果其中有多个关键数的话 按照其输入顺序的逆序输出. 输入:     输入数据包含多个用例,每个用例首先包含一个整数n,然后接下来一行有…