uvalive 3231】的更多相关文章

/** 题目: uvalive 3231 Fair Share 公平分配问题 链接:https://vjudge.net/problem/UVALive-3231 题意:有m个任务,n个处理器,每个任务有两个候选处理器,只要其中一个运行,该任务就能执行. 不同任务的两个候选处理器,至少有一个不同. 求任务数最多的那个处理器所分配的任务数尽量少. 思路:二分+最大流 左边是任务,s->u,cap = 1. 如果任务u和u的候选处理器v,u->v, cap = 1. 右边是处理器,二分mi.所有处…
Fair Share Time Limit: 3000ms Memory Limit: 131072KB This problem will be judged on UVALive. Original ID: 323164-bit integer IO format: %lld      Java class name: Main   You are given N processors and M jobs to be processed. Two processors are specif…
3231 - Fair ShareAsia - Seoul - 2004/2005You are given N processors and M jobs to be processed. Two processors are specified to each job. To processthe job, the job should be allocated to and executed on one of the two processors for one unit of time…
题目要求给m个任务分配给n个机器,但最后任务量最多的那个机器的任务量尽量少,利用最大流,在最后的汇点那里设置关卡,二分结果,把机器到最终汇点的容量设置为该值,这样就达到题目条件,这样跑最大流 还能把m个任务跑完(最终流量为m),则可行,继续二分 用的dinic #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <vector>…
UVALive - 4108 SKYLINE Time Limit: 3000MS     64bit IO Format: %lld & %llu Submit Status uDebug Description   The skyline of Singapore as viewed from the Marina Promenade (shown on the left) is one of the iconic scenes of Singapore. Country X would a…
UVALive - 3942 Remember the Word A potentiometer, or potmeter for short, is an electronic device with a variable electric resistance. It has two terminals and some kind of control mechanism (often a dial, a wheel or a slide) with which the resistance…
UVALive - 3942 Remember the Word Neal is very curious about combinatorial problems, and now here comes a problem about words. Know- ing that Ray has a photographic memory and this may not trouble him, Neal gives it to Jiejie. Since Jiejie can’t remem…
3231 小吃  时间限制: 1 s  空间限制: 16000 KB  题目等级 : 黄金 Gold 题解  查看运行结果     题目描述 Description 这里简直是吃货的天堂,小吃太多了.数不胜数. 假设岛上有N种小吃,每种体积Vi,美味度Wi. 设某吃货旅行者的食量C,求他能吃到食品的最大美味度. 输入描述 Input Description 两个正整数N  C N个正整数,Vi N个正整数,Wi 输出描述 Output Description 最大美味值 样例输入 Sample…
题目传送门 /* 题意:本来有n个雕塑,等间距的分布在圆周上,现在多了m个雕塑,问一共要移动多少距离: 思维题:认为一个雕塑不动,视为坐标0,其他点向最近的点移动,四舍五入判断,比例最后乘会10000即为距离: 详细解释:http://www.cnblogs.com/zywscq/p/4268556.html */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath&…
题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4156 题目拷贝难度大我就不复制了. 题目大意:维护一个字符串,要求支持插入.删除操作,还有输出第 i 次操作后的某个子串.强制在线. 思路1:使用可持久化treap可破,详细可见CLJ的<可持久化数据结构的研究>. 思路2:rope大法好,详见:http…