【LeetCode】88 - Merge Sorted Array】的更多相关文章

Merge Sorted Array Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initializ…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 新建数组 日期 题目地址:https://leetcode.com/problems/merge-sorted-array/description/ 题目描述 Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Not…
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note:You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initi…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: You may assume that nums1 has enough space (size that is g…
合并两个有序的list 把排序好的nums2插入nums1中,假设nums1这个vector的空间永远是够的 思路:倒序!! class Solution { public: void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { , i2 = n - , k = m + n - ; //完成的最终长度为m+n,末尾的index是m+n-1 && i2>=){ //倒…
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note:You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initi…
1. 题目 1.1 英文题目 You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively. Merge nums1 and nums2 into a single array sorted in non-de…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/#/description 题目描述 Given an array where elements are sorted in ascending order,…
#-*- coding: UTF-8 -*-class Solution(object):    def merge(self, nums1, m, nums2, n):        """        :type nums1: List[int]        :type m: int        :type nums2: List[int]        :type n: int        :rtype: void Do not return anything,…
Problem: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Solution: 复习一下BST的基本性质:简而言之,对于BST中任意结点x,若其有左右结点 l 或 r ,需满足 l.key ≤ x.key ≤ r.key BST的性能(基本操作耗时)与树高成正比,可改进为较为高效的平衡二叉树,即保持整棵树左右均匀,任意左右子树高度差不大于1 如…